'NEW' alternate illustrated solution to Rubik's cube puzzle

[justgeorgeous]

NEW solution booklet for sale $12.50 usd (free postage to anywhere in the world).See
http://www.members.iinet.net.au/%7Ejustgeorgeous/solvingRubikscube.html
or
http://ubuyonline.com.au/rubik_cube.html
or buy on ebay (pay by Paypal)
http://shop.ebay.com.au/merchant/justgeorgeous

 

[justgeorgeous]

see also http://www.youtube.com/watch?v=upub1rOvfqI

 

[pinoycuber]

lawl we need to buy it ?

 

[pcharles93]

You do realize that storebought cubes come with a beginner's solution already, right? So, if you buy a cube, you get the knowledge to solve it for free.

 

[Sg.Speedcuber]

Is the method even fast?I will still stick to fridrich.do you even use that method?

 

[DcF1337]

If you have common sense, you wouldn't buy it.

Knowledge should be free. The Internet is all you need.

 

[Stefan]

Congratulations, you guys have successfully missed his point. I suggest you read his page again and watch his video again.

I intend to buy tonight unless something posted until then convinces me not to (just saying that because I remember the recent blindsolving dvd incident, although this thing here is obviously different).

 

[DcF1337]

Congratulations, you guys have successfully missed his point. I suggest you read his page again and watch his video again.

I intend to buy tonight unless something posted until then convinces me not to (just saying that because I remember the recent blindsolving dvd incident, although this thing here is obviously different).

Okay, I JUST read his page again, but this time more thoroughly. It IS indeed quite different, since it starts with the opposite faces first. I apologize for my ignorance.

I wonder how fast it can go, though.

 

[rachmaninovian]

it is just a corners first solution? -.-

EDIT: lol i watched the video again and concluded that i was being stupid xD

 

[Stefan]

And opposite faces here means like Guimond, not like Ortega. Then apparently the same is done with the other two pairs of opposite sides before the pieces are finally solved. I could be wrong but I think it's possible that not a single edge or corner gets solved until that last phase.

Don't know how good the method is, but at least it's indeed new to me. Closest thing I know is Ryan Heise's Human Thistlethwaite method. That one however is certainly not aimed at beginners, while this one explicitly is. Also, the photos of the booklet show that it appears to be quite nicely done.

 

[DavidWoner]

Interesting method, a sort of reduction method for 3x3 I suppose? I was able to complete the opposite sides with a bit of work, but got stuck on the final stage. I gathered from the video and the opposite sides thing that the idea is to reduce it to a state where it is half-turn solvable. someone correct me if I am wrong on this. I have found a few cases that cannot be solve with only half turns, but I can usually reduce them to M' U2 M U2 etc. I got a few parity cases like UF->BD, DFR->DLB although is may be due to my method of solving opposite sides.

 

[qqwref]

I have found a few cases that cannot be solve with only half turns, but I can usually reduce them to M' U2 M U2 etc.

(R2 F2 R2 U2)2. But of course you'd want to do M' U2 M U2 for a speed method.

I got a few parity cases like UF->BD, DFR->DLB although is may be due to my method of solving opposite sides.

This is indeed a parity case (1/2 chance) if you just solve the opposite sides to opposite colors without worrying about whether it's half-turn solvable. As you saw you can get it into either a 2-swap of corners and 2-swap of edges (such as N perm) or a 3-cycle of corners (such as (UFL,URB,DFR)). I don't know of any quick way to resolve this so I'd be interested in seeing how this method works it out.

Interestingly you can solve the half turns only case entirely intuitively using only intuitive blockbuilding and the move sequences M' U2 M U2 and (R2 U2)3, using a Petrus type method. I doubt this is the method employed, but if you can get to this position more or less intuitively it's a really nice no-alg finish.

 

[Stefan]

I gathered from the video and the opposite sides thing that the idea is to reduce it to a state where it is half-turn solvable.

I doubt it, and this is also what convinced me that this is not just Ryan's Human Thistlethwaite. Recognizing half-turn-solvability isn't quite trivial. Of course you could go for something stronger which includes half-turn-solvability and is easier to detect (that's what I did when I implemented my almost-Thistlethwaite solver a while ago). But I just don't think this is the easiest way, so this method might very well do something else.

If you have common sense, you wouldn't buy it.
Knowledge should be free. The Internet is all you need.

Do you also demand Harry Potter and the New York Times etc to be available online for free?

And for the curious who don't know them yet:
Ryan's Human Thistlethwaite
Jaap's description of Thistlethwaite

 

[abr71310]

Man, now I'm gunna wanna know what's in the darn thing.

 

[Kirjava]

Do you also demand Harry Potter and the New York Times etc to be available online for free?

I remember getting the last book in PDF from 4chan before it was out.

If you get a copy, you should scan it for us XD.

 

[Wacky]

A poster starts a thread to sell something with

Please do not forget that I have intellectual property and copyright rights on this booklet, so please do not make copies for your friends.

and it's only been like, 2 pages into the thread, geez...

Moving on, the method sounds interesting and may offer a new approach to cube solving, but the move count in the video seems to be over 70, is that typical?

I should point out that Fridrich/Petrus/Heise/Human Thistlewaite/Roux/Waterman etc. all have lower move counts around the 45-55 mark, and some have pretty, intuitive, and interactive explanatory webpages, for free, and that beginner variants of those methods can take around 70 moves or less.

So should probably warn you that if your method doesn't offer significant improvements on that, you may potentially find that trying to sell copies of your work for money may be difficult.

P.s. do you happen to know Dr. Jamie Simpson?

 

[hr.mohr]

Something about Twenty20 cricket:

http://www.thewest.com.au/default.aspx?MenuID=4&ContentID=116230

Isn't cricket a game that lasts like two weeks? No wonder he took up cubing while waiting for the bloody match to end!

 

[Stefan]

I'm in the process of ordering it now (have to ask for details).

If you get a copy, you should scan it for us XD.

If by that you mean I'll read it and talk about it a bit, then yes. I won't copy and upload it, of course. This guy even wants to sue some cricket organization for not calling him the inventor of this Twenty20 variant, and he already emphasized copyright for his cube solution booklet.

 

[a small kitten]

http://www.thewest.com.au/default.aspx?MenuID=4&ContentID=116230

Yeah, he got GGed by the ICC. I don't know how copyright law works in Australia but I'm pretty sure intuitive cubing moves shown in the first scan do not qualify as things original to him. However, his diagrams and the more complicated moves that he generated are copyrightable.

I don't know if he is still around on the forums, but I'd like to know a couple of things:

The method doesn't look particularly finger friendly due to E turns. Is there a way around that?

How fast is the method if you master it? Can you give us an estimation?

If it is too awkward for speedsolving, can you use it for anything else?

 

[ChromisElda]

Something about Twenty20 cricket:

http://www.thewest.com.au/default.aspx?MenuID=4&ContentID=116230

Isn't cricket a game that lasts like two weeks? No wonder he took up cubing while waiting for the bloody match to end!

Haha cricket's long but not that long

there's 5 day matches, 3 day matches, One day matches, and now these 20 over matches which are over in just a few hours (say 3?)