You will have less problems, when you are more used to it. Trying things sighted is a good idea for the sart.
I'm a slowcucber (the goal is to get it at all with not too much effort, and speed isn't that important) and I examine the cube before the memo for solved or flipped edges. After that, I can calculate the number of expected letters (11 - solved + flipped) - this all can be done in a few seconds. I keep that number in mind and if a new cycle appears afterwards while memoing, I just have to add 1.
Advantage: I can memo quite fluently and don't have to search for missing edges after half of the memo (which I would forget quite soon). And I know, what is still to come and I don't need to put the fingers onto the stickers (which I do only for the centers in bigblind).
Maybe that can help you at the start, 10 seconds more in the beginning, but a much more easier memo.
Another tip: if my buffer-piece is flipped, then I lift a foot, so at the end of the memo, I know, whether I got the orientations right (or at least an even number of errors

). Keep in mind: if you start a new cycle with a flipped piece, the buffer piece is flipped, too.
Three ideas, which may help to unterstand cycles and flipped edges:
1. You start a new cycle, when your buffer-piece is solved. So at the start of the new cycle, the buffer-piece goes to the piece, with which you start the new cycle. So at the end of the cycle, this piece must be solved (again) to put the buffer-piece back.
2. The new-cycle-piece is involved twice and so you have an additional "tour" and you have to add 1 to the number of letters.
3. If you have a flipped edge (ie front-right) and you solve it like JP, then the J starts a new cycle and the P ends this new cycle.
(To 1: a really fast method could be, to take a new buffer and new target with the new cycle. I.e. if J isn't solved, you could take J as new target and R as new buffer - perhaps easiest done with cube-rotations. This would decrease the number of moves (J would be solved with an E2 or M2 after cuberotations), but is surely no thing for a beginner - but maybe it helps a bit to understand, why new cycles have to be like they are.)
For new cycles take the pieces, which can be solved fast (fastest is A because it's only an M2).
Or: if I have to start a new cycle, I try to get an middle-slice-edge oriented right (as the second piece in that new cycle). I don't like them flipped, because I don't like the algs for them - but this is maybe a bit too slowcubing