The 3x3x3 Example Solve Thread

[JTWong71]

Scramble: R' B' D' F2 R2 F R2 L2 U2 B2 R F' B2 U L2 B F' D2 L F' R L' B R2 F2

R L U B R2 B2 F' u F2 //2x2x3
R2 U R' f' U2 f //EO + CP
U' R U2 R U2 R2 U2 R U' R U2 R U2 R' //2GLL + F2L-4
29 STM, Petrus method with CP at the EO Step, and with an easy F2L Block

Next: L2 B2 F2 D2 R2 D' L2 B2 R2 B2 R2 B' D' B' R' D' U' F' L2 D2 F2

 

[porkynator]

Next: L2 B2 F2 D2 R2 D' L2 B2 R2 B2 R2 B' D' B' R' D' U' F' L2 D2 F2

F' U D' R D2 F' D F //Orient corners and many edges (8/8)
R' D' R' D U' B D B' //Orient all edges (8/16)
U2 B2 D R2 U' R2 F2 //Domino solve, first part (7/23)
D B2 D' R2 F2 D' L2 D F2 R2 U //Finish (11/34)

Next scramble: U2 B2 R2 U B2 L2 F2 R2 U F2 L U' B' U' B' R2 B2 F D R2 D

 

[G2013]

Next scramble: U2 B2 R2 U B2 L2 F2 R2 U F2 L U' B' U' B' R2 B2 F D R2 D

y' F R U' R z2 y L F' L' D' //Cross wtf
L' U L U2 L U L' //1st pair
R' U' R [U y] L U L' //2nd pair
y' R' U2 R U' R' U [R //3rd pair
R] U' R' U R U R' //4th pair
U2' f R U R' U' f' U F R U R' U' F' //OLL
U R U R' [U' D] R2 U' R U' R' U R' U R2 U D' //PLL

66 moves (the [R R] was a quite obvious cancellation for me so I wrote both moves together), 5 rotations

Next scramble: D' R2 D' F' B2 R2 B U B U L' F2 U' R2 F2 L2 B2 U' R2 B2 U2

 

[Bindedsa]

Next scramble: D' R2 D' F' B2 R2 B U B U L' F2 U' R2 F2 L2 B2 U' R2 B2 U2

It's been a while:
U R L F U2 F
U L U L'
r' F r U2 y R U R'
U r' F' r2 B r'
y' R U' R' U R U' R'
R2 D' R U' R' D R U' R U R' U R U'
Nothing very exciting, a pretty easy scramble. I might have done a different cross + 1 in a normal solve, but I liked this
Next scramble: R2 F2 D2 U2 F L2 B D2 F U2 B' D' R' U2 F' R2 U L F' R F

 

[Daniel Lin]

Next scramble: R2 F2 D2 U2 F L2 B D2 F U2 B' D' R' U2 F' R2 U L F' R F

R F L' D F' B' // bad cross
U' R U R' U2 F' L F L'//bad 1st pair
U' R' U' R U y R' U' R//2nd
R U2 R' U2 R U' R'//3rd
L' U' L L F' L' F//4th
R' U' F' R U R' U' R' F R2 U2 R' U2 R U//zbll
50 htm

next: L' D2 B2 L2 D2 F2 U2 R D2 U2 L B' R' D2 R' U' L D B U2 R

 

[Attila]

next: L' D2 B2 L2 D2 F2 U2 R D2 U2 L B' R' D2 R' U' L D B U2 R

U' L2 B F R U' F D' U F' R2 U2 R U D' F' D R' U D' F2 U D' L' U L2 D' F2 B2 U' F2

U' L2 B F R U' F D' U F' orient corners and 4 edges,
(F2 U F2 B2) 2 more edges,
R2 U2 R U D' F' D R' U D' F2 U D' L' U L2 D' LSE.



next: D2 B' U2 B' L2 U2 F U2 L2 D2 F D' F2 R U' F2 L D' R2 D F'

 

[G2013]

next: D2 B' U2 B' L2 U2 F U2 L2 D2 F D' F2 R U' F2 L D' R2 D F'

your solution doesn't work for me :/ maybe you mis-wrote a move
EDIT: I get it, the 2nd step was done on the inverse scramble

F' B' R' U B U2 L' x2' //Cross
R' U' R y U2 R' U' R //1st pair
L' U L U2 L U L' //2nd pair
U L' U2 L U L' U' L //3rd pair
y' R' U R //4th pair
U2 R U R' U R U2 R' //AUF+Sune
U' R2 U R' [U' y] (R U R' U')2 R U R' y' R U' R2' //Worst PLL alg maybe, or worst execution of an alg

60 moves if I counted correctly, 5 rotations
my solves are super inefficient, I must check that out...

 

[Daniel Lin]

U' R2 U R' [U' y] (R U R' U')2 R U R' y' R U' R2'

[U' R2 U R' U' y F':F triplesexy F']
or you could do [z R U2 R2:F triplesexy F']

what scramble is next?

 

[G2013]

woops, let it be D2 L' B R2 F2 L' R2 F2 L' F L2 R B2 L' B' D2 R' F R2 D'

 

[Tommy Kiprillis]

woops, let it be D2 L' B R2 F2 L' R2 F2 L' F L2 R B2 L' B' D2 R' F R2 D'

D R2 F' Rw' U Rw D2 [Cross]
U L' U' L [F2L#1]
U L U L' U2 R' U' R [F2L#2]
R' F' R U R U' R' F [F2L#3]
Dw L' U L F' Rw U Rw' [F2L#4]
U2 Lw' U' L U' L F' L' F Rw' F2 R [OLL] (i need a better OLL alg for this pls halp)
U' R U R' U' R' F R2 U' R' U' R U R' F' U' [PLL]

 

[JTWong71]

U2 Lw' U' L U' L F' L' F Rw' F2 R [OLL] (i need a better OLL alg for this pls halp)

I do:
M (L' U' L U' L' U2 L) U' M'...
Simplified for easier memorization:
M (Lefty Sune) U' M'

Random Scramble: U L R D2 L' B2 D2 R U2 F D R D' L R2 F U2
x //Inspection
r U2 F' U L D' //XCross
U' F R U2 R2 U' F' U' R //Multislot F2L-2/3
U R U2 //F2L-4 (Cancelled Moves)
R' U' l' U l F' //OLL(CP)
M2 U' M' U2 M U' M2 U //EPLL
32 STM

Next Scramble: R' U' B2 D2 U' F2 D2 U' R2 B2 R B' D U R' D2 F2 D2 F2

 

[JTWong71]

Scramble: R' U' B2 D2 U' F2 D2 U' R2 B2 R B' D U R' D2 F2 D2 F2

z //Inspection
R2 B2 D2 //First Block
U R2 U2 R U2 r U' R' U2 r2 //Second Block
U' R U R' U' R' F R F' //CMLL
U' M' U M' U //EO + L/R Edges
M U2 M' U2 //Finish L6E
31 STM, Roux Method

Next Scramble: B R2 B2 R' U2 R2 D2 L B2 F2 R2 D R' U' R U' L2 R D2 B'

 

[porkynator]

Next Scramble: B R2 B2 R' U2 R2 D2 L B2 F2 R2 D R' U' R U' L2 R D2 B'

For this scramble, I have tried something I have had in my mind for quite a long time.
I have found this solution without using any cube (physical nor simulator).
As I would do in a blind solve, I solved edges and corners separately with commutators.
First, I tracked every edge to see the permutation cycle (and check if there were any flipped). This was easier than I had thought.
I have found this.

(UR BU DR FL LB FR BD DF UF UL)(DL RB)

Now I use commutators to "solve" these cycles. Actually I "copy" these cycle, so I am matching the scramble instead of solving it. No big deal, I just have to invert the final solution to get one for this scramble.
The easiest way would be to just do a blind solve, but I struggled I little bit to save moves, in order to see if I could get under the 80HTM limit for a legal FMC solve.
I could break the first big cycle into 3-cycles in any order, and I choose this one. There are probably better ways to solve edges, but I didn't want to think to much about it.

(A) (UF UL UR) = [F2 U: M', U2] = F2 U R' L F2 R L' U F2
(B) (UF BU DR) = [M', B' R B] = R' L U' R' U R L' B' R B
(C) (UF FL LB) = [L' U L, E] = L' U L U D' B' U' B U' D
(D) (UF FR BD) = [U2: M, U R U'] = U2 R L' B R B' R' L U R' U

Then I solve the 2-2 cycle left.

(E) (UF DF)(DL RB) = [U B U': (L2 F2)3] = U B U' L2 F2 L2 F2 L2 F2 U B' U'

Same thing for corners. One was twisted, so I use a different notation for the permutation.

UBL->BLU
UFL->LFD->DBR->UFR->RFD->LBD->URB->FUL

(1) (UBL UFL LFD) = [U', L D L] = U' L D L' U L D' L'
(2) (URB FUL UBL) = [F R' F', L] = F R' F' L F R F' L'
(3) (UFR RFD LBD) = [R U R', D2] = R U R' D2 R U' R' D2
(4) (DBR UFR URB) = [D: B2, D F2 D'] = D B2 D F2 D' B2 D F2 D2

Now I can use this commutators in any order, as long as the relative order of the pieces of the same kind remains the same (i.e. I cannot use (2) before (1), but I can do either (A) (B) (1), (A) (1) (B), (1) (A) (B)). To cancel more moves, I used this order:

(1) (A) (2) (B) (C) (D) (E) (3) (4)

At this point I checked the solution on my cube and it was extremely satisfactory to see everything going as I expected
Inverting and cancelling gives the following solution:

D2 F2 D' B2 D F2 D' B2 D R U R' D2 R U' R' U B U' F2
L2 F2 L2 F2 L2 U B' U2 R U' L' R B R' B' L R' U' D' B'
U B D U' L' U' L B' R' B L R' U' R U R F R' F' L'
F R F U' L R' F2 L' R U' F2 L D L' U' L D' L' U

alg.cubing.net

79 HTM, just under the limit
There are many ways to improve this "method", but I just wanted a success, and I am satisfied with the result.

Next scramble: U L2 U2 L2 D' B2 F2 U' B2 R2 D B' F2 L2 B L D R2 F2 U'

 

[irontwig]

D2 R B' D R2 L' U R' U' L U R D' R D F U' B2 U F' U' B' D U' L U2 L' U D (29)

Just barely sub-30, didn't have time to explore R and U EO.
Almost linear skeleton:
D2 R B' D R2:U D' R D [2x2x3]
U'.B D U' L U2 L' U D [L4C]

.=U F U' B2 U F U' B2
:=L' U R' U' L U R U'

Interesting stuff on the inverse with parity: D2 B' D' B' [EO] L R2 U' L U' R' D R [Blocks]

Next: R2 B L2 U' R2 D L F R' F' U2 D2 F U2 L2 F2 R2 U2 B2

 

[Lid]

Next: R2 B L2 U' R2 D L F R' F' U2 D2 F U2 L2 F2 R2 U2 B2

Let's CFOP ...

y2 M D R2 B' u' // X
R U2 R2 U' R // 1st pair
B' U' B U R U R' // 2nd pair
d R U2 R' U' R U R' // 3rd pair
L' U L d' L U L' // 4th pair
M' U' M' U' M' U' M2 U' M' U' M' U' M' U' // LL

next: R2 D' L2 D B2 F2 D L2 U F2 U' B R' D2 F L2 U' B2 R2 F' U'

 

[JTWong71]

next: R2 D' L2 D B2 F2 D L2 U F2 U' B R' D2 F L2 U' B2 R2 F' U'

Trying out the Petrus Method...
Reconstruction of 15.16 Second Solve
2.57 TPS

y //Inspection
F' L (U2 D2) L2 //2x2x2 Block
U2 F' U' R2 F' U R2 F' R //2x2x3 Block + EO
y' U R' U2 R U' R' U R' //1x2x2 Block
U' R U R' //F2L
U' R U R2 U' R2 U' R2 U2 R2 U2 R' U2 //2GLL

Next: L B2 L2 B2 F2 L' U2 B2 U2 B2 L2 U B D' R2 F2 L U2 R F' R

 

[Ksh13]

Next: L B2 L2 B2 F2 L' U2 B2 U2 B2 L2 U B D' R2 F2 L U2 R F' R

R F R' B2 U L // Cross (6/6)
E L' U' L // 1st Pair (4/10)
d' R U R' // 2nd Pair (4/14)
U' R U R2 x' U' R' U x // 3rd Pair (7/21)
y' R U' R' U R U R' // 4th Pair (7/28)
R' U' R2 D R' U' R D' R2 U2 R // ZBLL (11/39)

39 STM CFOP

Next: B' L2 B R2 U2 F U2 L2 D2 L2 U' R D2 L2 F2 D U' F' D2 F'

 

[JTWong71]

Next: B' L2 B R2 U2 F U2 L2 D2 L2 U' R D2 L2 F2 D U' F' D2 F'

y' //Inspection
R U2 B2 U L' //2x2x2 Block
U' F2 U2 R' (U) F (U2) R F //2x2x3 + EO
U2 R U' R U' R2 U' R2 //F2L
U' R U2 R' U' R U' R //ZBLL-1
D' R U2 R' D R U2 R //Finish ZBLL (L3C)
38 STM Petrus

Next: R' U' R U D L' D' R2 F' U' L2 F2 U R2 U2 B2 R2 U' F2

 

[Attila]

Next: R' U' R U D L' D' R2 F' U' L2 F2 U R2 U2 B2 R2 U' F2

R F' R2 U2 D' B orient corners,
D B' R L' D orient edges,
B2 U2 R2 F U F2 B2 D' domino reduction,
F B D2 F B R2 F'


next: U' L2 U2 B2 D2 B2 L2 U' B2 U' F2 R F' U' F' R B' U2 F' U F'

 

[JTWong71]

next: U' L2 U2 B2 D2 B2 L2 U' B2 U' F2 R F' U' F' R B' U2 F' U F'

33 STM
R2 B' U' R F' L2 U R2 //2x2x3 Block
U R U R' //EO + Preserve Pair
d R2 U R' //F2L-1
L U2 R' U' R U2 L' //Winter Variation
U' r' U L' D2 L U' L' D2 L2 //CPLL (L3C)

Next: F2 R2 U2 L2 D' B2 D F2 R2 L D R U2 L D L' B' F R2