Please help! Need a 4x4 commutator that does the following...

[Stefan]

Red socks are impossible.

 

[joey]

Okay, I was slightly worried when I saw you had replied. I had feared that you might have been able to.

 

[Stefan]

You're confusing me with these interacting past tense variations whose names I don't know just to teach me a lesson, aren't you?

 

[joey]

It's all subconscious Stefan.. all subconscious.

 

[qqwref]

Hi. I solved it with r plus commutators. I can't quite figure out how to combine these all into one.

r [U' R' U r' U' R U r U' R' U, r2] [u' R2 u R b' R2 b R2 u R2 u' R b R2 b' u' R2 u, r2] [u' R u2 R2 u2 R' u, r']

Anything can be solved "using" commutators, but this case can't be solved with only commutators

 

[joey]

Hi. I solved it with r plus commutators. I can't quite figure out how to combine these all into one.

r [U' R' U r' U' R U r U' R' U, r2] [u' R2 u R b' R2 b R2 u R2 u' R b R2 b' u' R2 u, r2] [u' R u2 R2 u2 R' u, r']

Anything can be solved "using" commutators, but this case can't be solved with only commutators

Exactly Obviously, qqwref managed to find/wear and fully utilise his red socks.

 

[qqwref]

Red socks?

 

[joey]

You should read the last few posts P

 

[qqwref]

I did, but I don't get the part where red socks help you solve things :|

 

[joey]

Nor do I, we were just getting silly

 

[Kenneth]

Sock on this: (not the same case but...)

U2 l' U2 r 3D2 r' U2 r 3D2 M U2 l ... 3D2 is a triple layer D-turn = the swaps.

This commutator does a 3-cycle triplets of two centres and one edge each, a J-PLL in the second layer if you like. Obviously it solves edge parity... but also destroys some centres (solvable using commutators).

BTW: change 3D2 to only D2 and skip the last l and you got a nice 3-cycle edges in one layer ("A-PLL").

 

[shafiqdms1]

Joey, learn English. I can even solve it using red gloves.

Aha! But what about red socks?

Red socks are impossible.

oh crap that is impossible ;p