cmhardw
Premium Member
Just kidding! This hasn't been proven yet. You've just been
Surprise Challenged by Chris Hardwick!
There's only one Golden Rule:
Surprise Challenge Golden Rule) Do the challenge listed below within the next week.
Clarification of the #1 rule: If you clicked this thread, then you must do the challenge as described.
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Ok, here's the challenge!
3x3x3 Forced Turns Fewest Moves Challenge
You have a maximum of one week to complete the following challenge. The challenge is to solve the following scramble in the fewest number of turns (HTM) as possible. However, every 10th turn of your solution must be F' - these are the "forced" turns. This rule applies whether you solve the scramble or the inverse scramble. If you do choose to solve the inverse scramble, then every 10th turn of the solution you build must be an F'. This will result in every 10th turn of the solution to the scrambling algorithm, starting from the end of the solution, being an F. The F, or front layer, is fixed throughout the entire solve and is defined as the face that was on the front of the cube upon execution of the scrambling algorithm.
After each "forced" turn you may not turn the F layer again until the 2nd move after the forced turn. This means that you cannot simply undo the forced turn with an F immediately after. In fact, you can't turn the F layer at all immediately after the forced turn - but it is allowed again the 2nd turn after each forced turn. You must find your solution without the aid of any computer solver, use just your brain!
Remember, this surprise challenge is a bit different in that you may take up to a full week before posting your solution. Let's keep this interesting and submit all solutions before August 31. Try to surprise others with a link to this thread!
The scramble is listed below, good luck! Remember, you must do the challenge within the next week.
3x3x3 Forced Turns Fewest Moves Challenge: R' F R' D' U' F2 B U2 F2 L' F R2 U' B2 L R2 F' B2 D2 U' L2 U L2 B F2
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Fun Variation #1
Additional Rules and Clarifications for a more enjoyable (and difficult) challenge:
Clarification 1) If cube rotations are used at any point during the solve, then the front face is still defined as the face that was on the front of the cube when you applied the scrambling algorithm. This face must be turned once counterclockwise every 10th turn (whether you use cube rotations or not)
Clarification 2) You may not use any computer solvers, but you can use computer aids to see if your solution works. Just don't use ACube to find useful 8 or 9 move transformations ;-)
Additional Rule #1) Ok now the additional rule that makes this more fun. Every 9th and every 11th turns may not be turns of the F layer. Remember, by F layer I mean that layer that was the front face as you applied the scrambling algorithm. For example, say this is the green face. If you rotate the cube during your solve, then every 9th turn and every 11th turn, may not be turns of the green layer. In addition, the "forced" moves from the original challenge still apply. This means that every 10th turn must be to turn the green layer counterclockwise one turn in my example.
--/EDIT--
Fun Variation #2
For those who have completed the above challenges, or for those who want to try the most difficult version of the challenge of all, then try the following fun variation.
All of the rules mentioned below apply for Fun Variation #2:
1) The front face must be turned once counterclockwise every 10th turn of your solve. The front face is fixed throughout the duration of the entire solve, and is defined as the face that was on the front of the cube when you applied the scrambling algorithm.
2) If you do choose to solve the inverse scramble, then every 10th turn of the solution must follow rule #1 above. This will result in every 10th turn of the solution to the scrambling algorithm, starting from the end of the solution, being an F turn.
3) Every 9th and every 11th turn of your scramble may not be a turn of the front layer. The front layer is fixed through the duration of the solve and is defined as the layer that was on the front of the cube when you applied the scrambling algorithm.
3) You may not do more than 2 turns of parallel layers in a row. For example the sequence B F B' F' is not allowed as this counts as 4 turns of parallel layers in a row.
4) Cube rotations may be used, but you must turn the original front layer every 10th turn. Also, all of the above rules apply still. Cube rotations do not count as one of the turns of your solution.
5) The solution is measured in HTM, and thus slice turns are not allowed. The slice turn E must be written as either U D' or U D' y' and counts either way as 2 turns.
6) You may not turn the same layer twice in succession at any point during the solve. For example doing R R2 or R' R is not allowed at any point during your solve.
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Once again, Good Luck Everyone!
Chris
Surprise Challenged by Chris Hardwick!
There's only one Golden Rule:
Surprise Challenge Golden Rule) Do the challenge listed below within the next week.
Clarification of the #1 rule: If you clicked this thread, then you must do the challenge as described.
----------------------------------------------
Ok, here's the challenge!
3x3x3 Forced Turns Fewest Moves Challenge
You have a maximum of one week to complete the following challenge. The challenge is to solve the following scramble in the fewest number of turns (HTM) as possible. However, every 10th turn of your solution must be F' - these are the "forced" turns. This rule applies whether you solve the scramble or the inverse scramble. If you do choose to solve the inverse scramble, then every 10th turn of the solution you build must be an F'. This will result in every 10th turn of the solution to the scrambling algorithm, starting from the end of the solution, being an F. The F, or front layer, is fixed throughout the entire solve and is defined as the face that was on the front of the cube upon execution of the scrambling algorithm.
After each "forced" turn you may not turn the F layer again until the 2nd move after the forced turn. This means that you cannot simply undo the forced turn with an F immediately after. In fact, you can't turn the F layer at all immediately after the forced turn - but it is allowed again the 2nd turn after each forced turn. You must find your solution without the aid of any computer solver, use just your brain!
Remember, this surprise challenge is a bit different in that you may take up to a full week before posting your solution. Let's keep this interesting and submit all solutions before August 31. Try to surprise others with a link to this thread!
The scramble is listed below, good luck! Remember, you must do the challenge within the next week.
3x3x3 Forced Turns Fewest Moves Challenge: R' F R' D' U' F2 B U2 F2 L' F R2 U' B2 L R2 F' B2 D2 U' L2 U L2 B F2
--------------------------------------
Fun Variation #1
Additional Rules and Clarifications for a more enjoyable (and difficult) challenge:
Clarification 1) If cube rotations are used at any point during the solve, then the front face is still defined as the face that was on the front of the cube when you applied the scrambling algorithm. This face must be turned once counterclockwise every 10th turn (whether you use cube rotations or not)
Clarification 2) You may not use any computer solvers, but you can use computer aids to see if your solution works. Just don't use ACube to find useful 8 or 9 move transformations ;-)
Additional Rule #1) Ok now the additional rule that makes this more fun. Every 9th and every 11th turns may not be turns of the F layer. Remember, by F layer I mean that layer that was the front face as you applied the scrambling algorithm. For example, say this is the green face. If you rotate the cube during your solve, then every 9th turn and every 11th turn, may not be turns of the green layer. In addition, the "forced" moves from the original challenge still apply. This means that every 10th turn must be to turn the green layer counterclockwise one turn in my example.
--/EDIT--
Fun Variation #2
For those who have completed the above challenges, or for those who want to try the most difficult version of the challenge of all, then try the following fun variation.
All of the rules mentioned below apply for Fun Variation #2:
1) The front face must be turned once counterclockwise every 10th turn of your solve. The front face is fixed throughout the duration of the entire solve, and is defined as the face that was on the front of the cube when you applied the scrambling algorithm.
2) If you do choose to solve the inverse scramble, then every 10th turn of the solution must follow rule #1 above. This will result in every 10th turn of the solution to the scrambling algorithm, starting from the end of the solution, being an F turn.
3) Every 9th and every 11th turn of your scramble may not be a turn of the front layer. The front layer is fixed through the duration of the solve and is defined as the layer that was on the front of the cube when you applied the scrambling algorithm.
3) You may not do more than 2 turns of parallel layers in a row. For example the sequence B F B' F' is not allowed as this counts as 4 turns of parallel layers in a row.
4) Cube rotations may be used, but you must turn the original front layer every 10th turn. Also, all of the above rules apply still. Cube rotations do not count as one of the turns of your solution.
5) The solution is measured in HTM, and thus slice turns are not allowed. The slice turn E must be written as either U D' or U D' y' and counts either way as 2 turns.
6) You may not turn the same layer twice in succession at any point during the solve. For example doing R R2 or R' R is not allowed at any point during your solve.
----------------------------------------------
Once again, Good Luck Everyone!
Chris
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