What's considered lucky for M2/Pochmann?

SpeedCubing.Com said:
For blindfold solving a lucky case is defined by:
...
3) more than 3 corners are correctly positioned, or
4) more than 4 edges are correctly positioned.

@Stachu, the WCA regs have NOTHING about whether a case is "lucky" or not.

EDIT: And also Stachu, it can change. There are more scenarios of "lucky" for 3OP (orientation luckiness and permutation luckiness) where methods like M2/Old Pochmann only have permutation luckiness.
 
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I believe Mike Hughey suggested 20% (correct me if I'm wrong, Mike :)) solved as a general rule over all puzzles.
 
I believe Mike Hughey suggested 20% (correct me if I'm wrong, Mike :)) solved as a general rule over all puzzles.
I don't get credit for that - lots of people suggested 20% before me. I just jumped on the bandwagon. I guess I made it a lot more visible because I talk about it a lot more than other people. :)

But yeah, I think 20% is a good rule, and it even works pretty well for even-sized cubes (where many centers can be solved by properly orienting).
 
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