Shortest and LONGEST Resolving algs

Derrick Eide17

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what are some of the most shortest and longest cube solving algs you know?

Obviously shortest for me is
M2 E2 M2 E2 which does ABSOULTELY nothing xD :p

and longest i KNOW of is
L'U'R'D'

any others?

Edit: another REALLY long one
RU'RB2

omg.. so annoyingly long :p
 
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Derrick, try M E2 M E2 instead, it does a H-PML :)

My longest is a 18 QTM, it orients all four LL corners H case without moving the edges. (don't expect me to write it down, I must get a cube to do that =)

In the 80's I used a 32 turn alg for this case (double commutator 2 times), then I changed to 28 = four Sune's
 
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i remember after an old topic like this and checked and there was so my apologies for being a dumbass. and yeah i have been checking michaels page now and actually challenged some people on msn to do the 5x5 alg f' B2 x
until the cube got solved xD
Kris de asis actually tried 660 times + until he gave up.
I love telling people after when they ask: how many times do u have to do it to resolve?

and i can answer with
Oh not much... just... 978,120 times :p
 
I'm not an expert or anything, but I have a webpage on this: http://mzrg.com/rubik/orders.shtml.

I also wrote a program that would calculate the order of a sequence (number of times it takes to resolve) on 3x3, 4x4, or 5x5. Want it?

cool website :) I actually love the minimalistic web design. I was thinking of making myself an incredibly minimalistic website as well lately... hmmmm
oh and we have a lot of stuff in common btw :p
 
I remember doing FRBL one day when I was off school ill, and was bored. I kept losing count, but think it took 1260 moves until it returned to its starting position (315 cycles). Turns out that I was right =P
 
I would like to mention that it may be somewhat ambiguous what is meant by "resolving algs." You might or might not mean the same thing as the order of the alg (as defined by group theory).

The move x has order 4 even though (assuming you start from a solved cube) the cube remains solved after each time x is applied.

Also, 4x4x4 and larger cubes have indistinguishable centers that allow non-identities to seem like identities. For example (with lower case letters meaning single layer turns - the layer next to the face layer) , f' r' u' r U r' u r U' f has order 3 even though applied to a solved cube, it returns the cube to the solved state (unless it's a supercube). If you take a solved cube, and apply the move b before applying f' r' u' r U r' u r U' f, you see that the cube doesn't return to the same state you had before applying f' r' u' r U r' u r U' f.

It's also possible to reach an identity somewhere in the middle of one of the applications of the alg. A rather trivial example of this is R2 U2 R2 U2 R2 U2 R2 U2 which has order 3, but reaches an identity after one and a half times.

The following link ( http://www.geocities.com/jaapsch/puzzles/cubic3.htm#p34 ) gives the list of all the possible orders for positions in the <U,D,L,R,F,B> group (and how many of each). I wonder if someone has calculated all the possible orders for the <U,D,L,R,F,B,M,E,S> group (aka <U,x,y> group).
 
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