JasonDL13
Veteran
In the WCA Regulations it explains the solved state:
"10e) A puzzle is solved when all coloured parts are reassembled and all parts are aligned within the limits specified below:
10e1) For each two adjacent parts (e.g. two parallel, adjacent slices of a cube) of the puzzle that are misaligned more than the limit described in Regulation 10f, the puzzle is considered to require one additional move to solve (see "Outer Block Turn Metric" in Article 12).
10e2) If no further moves are required to bring the puzzle to its solved state, the puzzle is considered solved without penalty."
Okay. If it's one turn away it's +2 seconds. But what about for fewest move solving?
I cannot find something in fewest move solving that makes an exception to this. So does this mean someone can leave a cube one turn away in fewest moves and consider it solved?
If someone can correct me that would be great, or not, and it will have to be changed.
Thanks.
"10e) A puzzle is solved when all coloured parts are reassembled and all parts are aligned within the limits specified below:
10e1) For each two adjacent parts (e.g. two parallel, adjacent slices of a cube) of the puzzle that are misaligned more than the limit described in Regulation 10f, the puzzle is considered to require one additional move to solve (see "Outer Block Turn Metric" in Article 12).
10e2) If no further moves are required to bring the puzzle to its solved state, the puzzle is considered solved without penalty."
Okay. If it's one turn away it's +2 seconds. But what about for fewest move solving?
I cannot find something in fewest move solving that makes an exception to this. So does this mean someone can leave a cube one turn away in fewest moves and consider it solved?
If someone can correct me that would be great, or not, and it will have to be changed.
Thanks.