PLL 21 cases or 22

[~Phoenix Death~]

Lol. Read the description of the video. Then you'll see what I mean.

 

[Sir E Brum]

Well ZBLL is commonly cited as having 494 cases

472 of these are COLL + EP
21 are the PLLs (for OLL skips)
Which leaves one and that is the...
LL skip.

 

[blade740]

wait...there are 21 PLLs INCLUDING solved.

AAEGGGGHJJNNRRTUUVYZsolved.

 

[Chapuunka]

wait...there are 21 PLLs INCLUDING solved.

AAEGGGGHJJNNRRTUUVYZsolved.

...And F.

 

[StachuK1992]

Well, if you're going to count it *that* way, then aren't there 72 cases?

 

[shelley]

wait...there are 21 PLLs INCLUDING solved.

AAEGGGGHJJNNRRTUUVYZsolved.

...And F.

The what now? Stop making up fake PLLs.

 

[Jaysammey777]

Well, if you're going to count it *that* way, then aren't there 72 cases?

the only othere number I can come up with is 88( every U So after OLL if you do a U and then a T perm you could also have a U' and a T-perm) IDK if that made any sence

 

[Chapuunka]

Well, if you're going to count it *that* way, then aren't there 72 cases?

the only othere number I can come up with is 88( every U So after OLL if you do a U and then a T perm you could also have a U' and a T-perm) IDK if that made any sence

That's what I was thinking.

 

[StachuK1992]

No. I'm pretty sure it's 72

most cases count as four cases (like A, or U)
because there is a possibility of 4 different corner or edge cycles.

However
H perm only count once, really, because the angle which you perform the alg is kinda arbitrary
and Z perm counts as only two
etc

Just found this from a while ago:

There are 72 PLL's if you consider all starting orientations:

- H, the two N's and the solved case have only one starting orientation since they're completely symmetric
- Z and E have two starting orientations
- the remaining 16 cases have 4 starting orientations

4*1+2*2+16*4=4+4+64=72

After the PLL you can have 4 AUF's (U/U'/U2/nothing).

 

[StachuK1992]

H perm only count once, really, because the angle which you perform the alg is kinda arbitrary
and Z perm counts as only two
etc

That's still in terms of algs, not cases.

Look again at the post, young padawan.

 

[CuBeOrDiE]

No. I'm pretty sure it's 72

most cases count as four cases (like A, or U)
because there is a possibility of 4 different corner or edge cycles.

However
H perm only count once, really, because the angle which you perform the alg is kinda arbitrary
and Z perm counts as only two
etc

Just found this from a while ago:

There are 72 PLL's if you consider all starting orientations:

- H, the two N's and the solved case have only one starting orientation since they're completely symmetric
- Z and E have two starting orientations
- the remaining 16 cases have 4 starting orientations

4*1+2*2+16*4=4+4+64=72

After the PLL you can have 4 AUF's (U/U'/U2/nothing).

yes

 

[Joker]

I got an accidental quad x cross once.
Fail scramble. -slaps cube timer-

 

[blade740]

wait...there are 21 PLLs INCLUDING solved.

AAEGGGGHJJNNRRTUUVYZsolved.

...And F.

http://www.worldcubeassociation.org...ist of people who do the F Perm&single=Single

Nobody does the F perm. NOBODY.

 

[musicninja17]

Of course there are 22. The solved state is one of 22 attainable states on a scrambled last layer using legal moves. Therefore it's a case.

 

[TeddyKGB]

wait...there are 21 PLLs INCLUDING solved.

AAEGGGGHJJNNRRTUUVYZsolved.

...And F.

http://www.worldcubeassociation.org...ist of people who do the F Perm&single=Single

Nobody does the F perm. NOBODY.

This just made my day, although I use the F perm, even when I get a PLL skip I do the F perm twice just because I like it that much.

 

[musicninja17]

Why no F perm? I prefer it over some OTHER algs >_<

 

[blade740]

Why no F perm? I prefer it over some OTHER algs >_<

The F perm murdered my family.

 

[Forte]

No one does this either

But we love happy

 

[Kenneth]

Why no F perm? I prefer it over some OTHER algs >_<

The F perm murdered my family.

There you see, he admits it exsists

(R' Lw') U2 (M R) U Rw' U2 Lw' U' Rw U2 M' U'

 

[miniGOINGS]

@statue: I got 288 (in the sense that d' changes which case it would be). First corner (4 spots), second corner (3 spots), third and fourth corner (2 positions), first edge (4 spots), second edge (3 spots), third and fourth corner (only 1 because of parity). 4*3*2*4*3 = 288