Parity on a 3x3x5 (or 3x5x5) X-Cube

[t3ddy]

Hi guys.
I recently got my X-Cube (http://www.twistypuzzles.com/forum/viewtopic.php?f=15&t=25653&p=302655#p302655) and after some time i figured a way to solve it. It may not be the fastes or easiest, but there's no tutorials and i wanted to come up with a solution by myself.
I first bring it back into the original form, then solve the 3x3x3 part like 5x5x5 centers starting with the non-extended ones. This usually leaves a normal pll on the last extended part that i solve like i do on a 3x3x7 C4U-cube (align the 2 layers so that you can solve them both at once). this worked fine for the first 3 or 4 solves but this last time i got parity:

Two edge pieces of the last extension are swapped. i can't solve this with the method i use on the 3x3x7 as it's on the outmost layer, nor with any other parity algorithm i know. i think i have to swap two adjacent edge pieces on the white or yellow side in order to bring it back into a easily solvable state, but i can't figure out a way to do it without destroying everything.

So, does anyone know of a method or algorithm to solve this?
Thanks in advance,
t3ddy

 

[Username]

Picture please

 

[t3ddy]

for some reason i can't upload a pic, but here it is solved. My case would be that on the blue extension the blue/white and the blue/orange edge pieces have switched places.

 

[Stefan]

I think a quarter turn of the white side should fix your parity. So with blue on top and white on the right, I'd try (R U2)5.

 

[t3ddy]

wow, that solution was way easier than i exepected.

Thanks a lot

 

[Stefan]

Just a variation of (Rw U2)5 or (r U2)5 for the 4x4x4 and up, which everybody should know .
(The last U2 in all these can/should be omitted, but "(...)5" is shorter to say)