Parity issues of 6x6 v-cube

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are there other parity cases on a 6x6x6 v-cube than on a 4x4x4 / 5x5x5 cube?
I think there are many ways to combine pieces on a 6x6 cube to reduce it to a 3x3 or 4x4 or 5x5 cube. Are they equally good or bad?

cheers
Michael
 
are there other parity cases on a 6x6x6 v-cube than on a 4x4x4 / 5x5x5 cube?
I think there are many ways to combine pieces on a 6x6 cube to reduce it to a 3x3 or 4x4 or 5x5 cube. Are they equally good or bad?

cheers
Michael

Hi :-)

Yes the 6x6x6 has one more parity (parody :-P ) than 4x4x4. How this can be i leave it to you to figure it out yourself :)
Reduction to other size cube is possible - but not very feasible. I cannot think of ANY easy (!!!) way to reduce to for example a 3x3x3 cube.

- Per
 
I have never attempted a 6x6x6 solve, but my logic says that only the same KIND of parities (OLL/PLL) as on 4x4x4 are possible when using reduction. That kind of parity should be fixable the same way as on 4x4x4 although the actual layer/slice you perform the algorithm on will be different.

I hope to receive my V-Cubes this week so I can test this theory
 
If you pair up the centre edges, then the outside centre edges (like you would on a 5x5x5) you can end up with both 5x5x5 OLL parity and 4x4x4 OLL parity. That takes a while to sort out by using both of the parity algorithms used on a 4x4x4 and a 5x5x5.

And also, you can get a PLL parity.
 
On a 6x6 you can get parity during edgepairing, OLL parity and PLL parity. The two latter ones can be solved using expansions of the 4x4 P-algs, and the edgepairing can be solved using the same algs and some intuition :P

If you pair up the centre edges, then the outside centre edges (like you would on a 5x5x5) you can end up with both 5x5x5 OLL parity and 4x4x4 OLL parity. That takes a while to sort out by using both of the parity algorithms used on a 4x4x4 and a 5x5x5.

And also, you can get a PLL parity.

What is 5x5 OLL parity?!
 
reducing to 3x3

hmm, one could also combine the corners with their edges and inner single-colour-thingies and then the middle edges. This gives a perfect symmetrical big 3x3 cube made of 2x2 cubes :-)
 
hmm, one could also combine the corners with their edges and inner single-colour-thingies and then the middle edges. This gives a perfect symmetrical big 3x3 cube made of 2x2 cubes :-)

That idea has been tried for 4x4x4 (reducing it to a 2x2x2 cube), but it was way to slow. For reducing a 6x6x6 to a 3x3x3 it would be even worse.

However, it is fun to do and might be a nice way to create fake scrambles
 
Isn't (5x5x5) edge-pairing parity the same as (4x4x4) OLL parity?

It's not the same, even though you can use the same alg's to solve it. And what I meant earlier is this: 5x5 edge-pairing parity shouldnt be referred to as 5x5 OLL parity. Simply because it is not Orienting the Last Layer. Unless you wait with the parity until after the F2L :)
 
Isn't (5x5x5) edge-pairing parity the same as (4x4x4) OLL parity?

It's not the same, even though you can use the same alg's to solve it. And what I meant earlier is this: 5x5 edge-pairing parity shouldnt be referred to as 5x5 OLL parity. Simply because it is not Orienting the Last Layer. Unless you wait with the parity until after the F2L :)
I disagree about the first part. It is the same! It is just that on a 4x4x4 (or other even cubes) it's hard to recognise untill you reach the last layer.

I agree that OLL-parity and PLL-parity are bad names (OLL-parity can be solved during the center-stage with 1 quarter-turn). But what would be good alternative names?
Edge-Parity and Corner-Parity?
 
I disagree about the first part. It is the same! It is just that on a 4x4x4 (or other even cubes) it's hard to recognise untill you reach the last layer.

Well, when you put it like that :)

I agree that OLL-parity and PLL-parity are bad names (OLL-parity can be solved during the center-stage with 1 quarter-turn). But what would be good alternative names?
Edge-Parity and Corner-Parity?

No ideas about good names, but Permutation-parity and Orientation-parity is better than OLL- and PLL-parity

Solving OLL parity with a quarter turn isnt exactly widely used in reduction, is it? :) How would one do that? Counting all the oriented edges seems pretty timeconsuming :)
 
I disagree about the first part. It is the same! It is just that on a 4x4x4 (or other even cubes) it's hard to recognise untill you reach the last layer.

Well, when you put it like that :)

I agree that OLL-parity and PLL-parity are bad names (OLL-parity can be solved during the center-stage with 1 quarter-turn). But what would be good alternative names?
Edge-Parity and Corner-Parity?

No ideas about good names, but Permutation-parity and Orientation-parity is better than OLL- and PLL-parity

Solving OLL parity with a quarter turn isnt exactly widely used in reduction, is it? :) How would one do that? Counting all the oriented edges seems pretty timeconsuming :)
The quarter turn fix is not (yet) doable for a speedsolve. Analyzing cycles (odd=parity, even=no parity), using an even number of quarterturns if the cycles were even and an odd number of quarterturns otherwise for solving centers works.
Lars and I tried counting oriented/misoriented edges (not cycles) which works in theory, but has problems during execution.
So basically this is only doable for 4x4x4 FMC
 
I agree that OLL-parity and PLL-parity are bad names (OLL-parity can be solved during the center-stage with 1 quarter-turn). But what would be good alternative names?
Edge-Parity and Corner-Parity?

I think of them as "flipped cubies in a super edge" in place of OLL parity and "swapped super edges" in place of PLL parity. On big "even x even" cubes it is tough to distinquish which are flipped wrong/right, so I wait until F2L is done. On big "odd x odd" cubes, the middle cubie of the super edge indicates which way the cubies should be flipped, so I can fix it before F2L.
 
are there other parity cases on a 6x6x6 v-cube than on a 4x4x4 / 5x5x5 cube?
I think there are many ways to combine pieces on a 6x6 cube to reduce it to a 3x3 or 4x4 or 5x5 cube. Are they equally good or bad?

cheers
Michael

No, is you reduce first the two middle edges you have a 5x5 so you can have a 5x5 parity case, and solving the edges as a 5x5 make the 3x3 part you end with the same parities as a 4x4.

I can not think of a fast way to combine these parties.
 
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