OH equivalent to sub 10

I think sub-15 OH is about the same as sub-8 2H. So sub-16 is sub-9, and sub-17 is sub-10.
 
I don't think you can base the equivalent on "in-competition" data. Because given that, there are only a handful of official sub-10 avgs but at-home there's like, over 100 people with sub-10 avgs of 12. Also, 3x3 > OH in terms of popularity amongst people and in competitions.

Maybe a better comparison would be to take the number of people who claim to have a sub-10 avg of 12, and find the same number of people who have achieved a certain OH avg time. Like how many people do you think have achieved a sub-17 avg at home? Sub-18? What about sub-20? Would that be anywhere close to the amount of people who claim sub-10 avg?
 
Using that logic, someone that averages 8:10 2H is equivalent to 8:17 OH. You need to use something like percentages, not just add seconds like that.

If you're turning that slow for 2H you probably could turn that speed in OH too.
 
Why does an approximate model (which was only specified for a few values) need to apply for ALL values?

I suppose meteorologists should get new models because their predictive models don't work very well on long-range forecasts.
 
Why does an approximate model (which was only specified for a few values) need to apply for ALL values?

So in your original post, you aren't saying that the pattern continues. You think there is some barrier between OH 17 and OH 18 that doesn't exist between 2H 10 and 2H 11, so the pattern would stop. Is that correct?
 
Last edited:
Back
Top