cubefactorx
Member
- Joined
- Jun 30, 2018
- Messages
- 9
Hi all -
I had this idea many years ago and never took it very far. I've been out of the game for a while so apologies in advance if it has been hashed out previously.
The idea is to solve your F2L in traditional fashion, but along the way intentionally misplacing 2x F2L pairs diagonally from each other (i.e. FR&BL pairs or FL&BR pairs).
To visualize: apply R L U2 R' L' on solved F2L. Ref: FR&BL pairs are swapped. This would be a "finished" F2L with the swing pair method.
The idea here is that your final step in PLL will involve permutation of all the usual pieces + swapping F2L pairs back to their "true" home. The outcome is an algorithm subset for PLL that is very unique from the base PLL alg set. I have a very unrefined list of these cases that I will list below. Not all the cases are greatly optimized, but it should give a good feel for how things are different.
The great thing here is that the correction of pairs doesn't necessarily have to happen during a typical PLL. The OLL+SPF2L subset is very unique on it's own (in the limited number of cases I have checked anyway). It is possible one could arrive at an OLL case that is in the slower range during normal solving, but the OLL+SPF2L algorithm is faster by comparison. Then you would be left with a 'normal' PLL case to finish.
This should provide unique subsets for all manners of LL solving, and it is possible those subsets are more favorable overall compared to the normal approach.
SPF2L(PLL) cases:
You'll notice some normally fast cases are much worse, typically slower cases much better, and a small +/- on others. With probability of case occurence considered, this subset is 0.25HTM better and 0.68QTM worse compared to my personal base PLL set.
PLL HTM/QTM Algorithm
A1 15,16 U2 R' U [x] R U R U R U' [x'] U' R2 U R U F'
A2 15,16 U2 R U' [x'] R' U' R' U' R' U [x] U R2 U' R' U' B
U1 16,17 R U' L U' L' D' R U R' U2 R U R' D R' U'
U2 16,17 R D' R U' R' U2 R U' R' D L U L' U R' U
H 14,23 R2 F' U2 F2 R2 F' R2 U2 F2 R2 U2 F' U2 F2
Z 15,19 [x] L' u2 R' U2 L2 U R B' R' U R r2' U' R U'
E 10,15 [x] R2 u2 R L U2 M' U M2 U M2
T 9,9 r2 R U L' u2 R U' r' R2
J1 8,10 R U' L U2 R' U L' U2
J2 8,10 L' U R' U2 L U' R U2
N1 5,6 L' R' U2 R L
N2 5,6 L R U2 R' L'
Y 7,12 M2 U R2 B2 R2 U' M2
R1 14,18 R' U2 R L' U L U2 R' U' R L' U2 L U2
R2 14,18 L U2 L' R U' R' U2 L U L' R U2 R' U2
V 9,10 [x'] r U' R' u' R2 u R U r'
F 10,12 [z] U' D' M2 U R U' r2 D R' U
G1 13,18 R L U2 L2 R2 U2 L U L' U2 R U' L
G2 13,18 L' U R' U2 L U' L' U2 R2 L2 U2 L' R'
G3 13,18 L U' R U2 L' U L U2 R2 L2 U2 L R
G4 13,18 R' L' U2 L2 R2 U2 L' U' L U2 R' U L'
SS 15,19 z' U' r2 R' U L' U2'R U' R' U2 R L U'r2' U
I had this idea many years ago and never took it very far. I've been out of the game for a while so apologies in advance if it has been hashed out previously.
The idea is to solve your F2L in traditional fashion, but along the way intentionally misplacing 2x F2L pairs diagonally from each other (i.e. FR&BL pairs or FL&BR pairs).
To visualize: apply R L U2 R' L' on solved F2L. Ref: FR&BL pairs are swapped. This would be a "finished" F2L with the swing pair method.
The idea here is that your final step in PLL will involve permutation of all the usual pieces + swapping F2L pairs back to their "true" home. The outcome is an algorithm subset for PLL that is very unique from the base PLL alg set. I have a very unrefined list of these cases that I will list below. Not all the cases are greatly optimized, but it should give a good feel for how things are different.
The great thing here is that the correction of pairs doesn't necessarily have to happen during a typical PLL. The OLL+SPF2L subset is very unique on it's own (in the limited number of cases I have checked anyway). It is possible one could arrive at an OLL case that is in the slower range during normal solving, but the OLL+SPF2L algorithm is faster by comparison. Then you would be left with a 'normal' PLL case to finish.
This should provide unique subsets for all manners of LL solving, and it is possible those subsets are more favorable overall compared to the normal approach.
SPF2L(PLL) cases:
You'll notice some normally fast cases are much worse, typically slower cases much better, and a small +/- on others. With probability of case occurence considered, this subset is 0.25HTM better and 0.68QTM worse compared to my personal base PLL set.
PLL HTM/QTM Algorithm
A1 15,16 U2 R' U [x] R U R U R U' [x'] U' R2 U R U F'
A2 15,16 U2 R U' [x'] R' U' R' U' R' U [x] U R2 U' R' U' B
U1 16,17 R U' L U' L' D' R U R' U2 R U R' D R' U'
U2 16,17 R D' R U' R' U2 R U' R' D L U L' U R' U
H 14,23 R2 F' U2 F2 R2 F' R2 U2 F2 R2 U2 F' U2 F2
Z 15,19 [x] L' u2 R' U2 L2 U R B' R' U R r2' U' R U'
E 10,15 [x] R2 u2 R L U2 M' U M2 U M2
T 9,9 r2 R U L' u2 R U' r' R2
J1 8,10 R U' L U2 R' U L' U2
J2 8,10 L' U R' U2 L U' R U2
N1 5,6 L' R' U2 R L
N2 5,6 L R U2 R' L'
Y 7,12 M2 U R2 B2 R2 U' M2
R1 14,18 R' U2 R L' U L U2 R' U' R L' U2 L U2
R2 14,18 L U2 L' R U' R' U2 L U L' R U2 R' U2
V 9,10 [x'] r U' R' u' R2 u R U r'
F 10,12 [z] U' D' M2 U R U' r2 D R' U
G1 13,18 R L U2 L2 R2 U2 L U L' U2 R U' L
G2 13,18 L' U R' U2 L U' L' U2 R2 L2 U2 L' R'
G3 13,18 L U' R U2 L' U L U2 R2 L2 U2 L R
G4 13,18 R' L' U2 L2 R2 U2 L' U' L U2 R' U L'
SS 15,19 z' U' r2 R' U L' U2'R U' R' U2 R L U'r2' U