New Method/Concept Thread

How about this:

Inserting the last F2L pair while making the cross on top and permuting two of the LL edges. :) Kind of complicated, but it could mean a 1 look LL. There would be 6 possibilities for permuting the last 2 edges, excluding when they're already solved. So, 40 CLLs (I think) x 6 = 240. The cases would probably be slightly different, due to the mispermuted edges meaning mispermuted corners. However, it would probably still be 240 new cases to learn.

I hope that hasn't already been done before. :p

The last 2 Edges (oriented) have just 2 posible permutations that's ZZLL
 
The last 2 Edges (oriented) have just 2 posible permutations that's ZZLL

It is ZZLL, but the last 2 edges are more complicated than just swapped or not swapped. The set of 4 edges can be in different positions relative to the corners, so there are more than 2 permutations per COLL case. There are 168 ZZLL cases in total. (i think)
 
Definetly ther are 42 Corner cases just 2 Edge Cases and obviously they can be twisted against each other.

This twist also seems to be only 180° (there is for example only one H-Perm )
 
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