Ellis
Veteran
However, I would like to see an average of 5 or 12 on video. - sub 18 seconds.
I would too, actually.
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However, I would like to see an average of 5 or 12 on video. - sub 18 seconds.
Having been suspected of cheating a number of times, I'm sure that byu would have confessed if he was actually cheating. I believe him, and his abilites.
However, I would like to see an average of 5 or 12 on video. - sub 18 seconds.
However, I would like to see an average of 5 or 12 on video. - sub 18 seconds.
I would to, actually.
However, I would like to see an average of 5 or 12 on video. - sub 18 seconds.
I would to, actually.
Ok, when I return from my trip on Thursday, I'll try to make the video if I have time, I'll have a lot of other stuff to take care of.
I find your tutorials to be OK, but a bit rushed, which makes them difficult for beginners to comprehend. Here's an example
CubeGeek said:So now we flip the cube so that the white side is on the bottom. To solve the second layer we need to put in the 4 middle layer edges. First things first, find an edge piece that belongs to the middle layer. Belongs to the middle layer means it does not have yellow on it. Found it? Now look at the color of the edge piece that is not facing up. By using the U moves connect the not facing top color with its center.
CubeStation said:At this stage you should have completed the Bottom Layer. On this page you will learn how to solve the Middle layer using a simple procedure, thus enabling you to complete the First 2 Layers, or F2L as it is known in cubing jargon.
The middle layer contains edges which do not have the top layer colour (in this case Yellow). So the first thing you have to do is search for edges in the U layer (the top layer), which do not have stickers of the top colour. If there are no suitable edges in the U layer, see further on for dealing with edges trapped in the Middle layer. Next, turn the U-layer to match the colour around the side of the U-layer with the same colour centre (in the diagrams this is the red sticker). Then use the following steps to solve them!
Dan Harris also provides an animation so the people who do not fully understand the notation can see exactly how it works on a real cube.
Ok guys I have a confession to make. I'm a lie. I don't actually exist. I'm just a bot that has been putting my times into the database on the WCA. Anyone that thinks that they saw me actually saw a clever illusion. This is why I could never have physical contact with anyone, for they would go straight through me. I'm sorry, I'll go and clean up the mess soon...
Dude just wait my site is coming maybe by the end of June as I have my exams