loopover online puzzle

[Caden Fisher]

This 2x2 mean of 3 lol

 

[THE_V01DL0RD]

how many possible combinations are there for 2x2

 

[Jorian Meeuse]

how many possible combinations are there for 2x2

On an nxn, there are (n^2)! combinations

 

[THE_V01DL0RD]

On an nxn, there are (n^2)! combinations

This 2x2 mean of 3 lol View attachment 23745

(2^2)= 4
4!=10
There are 10 combinations
4 1 movers
4/10=40%
40% = 1 in 2.5
2.5^3=15.625
There is a 1 in 15.625 (or 6.4%) chance of getting 3 1 one movers in a row.

 

[Caden Fisher]

(2^2)= 4
4!=10
There are 10 combinations
4 1 movers
4/10=40%
40% = 1 in 2.5
2.5^3=15.625
There is a 1 in 15.625 (or 6.4%) chance of getting 3 1 one movers in a row.

Huh. Interesting.

Just did my first 10 by 10 solve!

 

[THE_V01DL0RD]

Huh. Interesting.

Just did my first 10 by 10 solve!

View attachment 23746

7:30ish 9x9

 

[THE_V01DL0RD]

Huh. Interesting.

Just did my first 10 by 10 solve!

View attachment 23746

how do you parity

 

[SpedCube]

first try: 2:54 (5x5)

 

[THE_V01DL0RD]

 

[THE_V01DL0RD]

who here can solve a 20 x 20

 

[VincentCuber]

I like 2x2 blind

 

[THE_V01DL0RD]

7x7 mo3

 

[Caden Fisher]

how do you parity

I kinda just messed around with it until it solved

who here can solve a 20 x 20

I‘ll try. I’ll post it when I’m done

 

[AJT17]

who here can solve a 20 x 20

I solved one, I would have gotten a sub 1 hour if I hadn't gotten parity, which I didn't know how to fix, but I got just over 1 hour

 

[Mastermind2368]

(2^2)= 4
4!=10
There are 10 combinations
4 1 movers
4/10=40%
40% = 1 in 2.5
2.5^3=15.625
There is a 1 in 15.625 (or 6.4%) chance of getting 3 1 one movers in a row.

Wouldn't that be 0.46% chance of getting three 1 move solutions in a row?

4!=4*3*2*1=24

4/24=1/6

100*(1/6)^3=0.46%

 

[THE_V01DL0RD]

Wouldn't that be 0.46% chance of getting three 1 move solutions in a row?

4!=4*3*2*1=24

4/24=1/6

100*(1/6)^3=0.46%

no because you forgot to take account the 4 one movers and the fact there are 10 combinations

 

[THE_V01DL0RD]

FIRST ONE TO SOLVE A 20x20 GETS A FREE COPY OF NEW SUPER MARIO BROS ON THE DS!
(you need a computer to recieve it i swear to god it's not a scam its on a app I found)

 

[Mastermind2368]

no because you forgot to take account the 4 one movers and the fact there are 10 combinations

How is there 10 combinations?

4!=4*3*2*1=24 combinations, not 10.

4 one-move solutions divided by 24 total combinations = 1/6 probability that any given scramble has a one move solution.

 

[THE_V01DL0RD]

How is there 10 combinations?

4!=4*3*2*1=24 combinations, not 10.

4 one-move solutions divided by 24 total combinations = 1/6 probability that any given scramble has a one move solution.

sorry about that. your right i thought 4!=4+3+2+1

 

[Deleted member 36445]

who here can solve a 20 x 20

I can do it Monday