Looping or Repeating Algorithms?

I understood that, but what miniGOINGS was implying, was that every algorithm is the Devil's algorithm.
 
No, that's not what he was implying. You're reading it wrong. He was saying "start from a solved position, and do the algorithm, and given enough time the cube will be solved again", not "you can solve any scramble with any algorithm".
 
That's only assuming the cube is already solved, he never said it was.

Please read the discussion about the devils algorithm.

hahaha true what i meant was any algorithm turns a cube from solved back into solved given time,, and i was watching the high school musical series at the same time :( so im not sure how many times i turned the cube but the trip was 6 hours

ive never had so many people argue over me before :) hahaha
 
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Maybe it took so long to repeat because you were too busy watching the movie and you actually repeated it several times before you noticed?
 
RU repeats, I used to play around with that back when i used the LBL method. :P

Repeats after you do it about 67-68 times if I remember

R U' repeats after 64 i believe, that must be what your referring to
Could we please not be stupid and only post when we actually have an idea about something, instead of remembering/believing incorrectly? (It's 63 for RU' and 105 for RU.)
 
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RU repeats, I used to play around with that back when i used the LBL method. :P

Repeats after you do it about 67-68 times if I remember

R U' repeats after 64 i believe, that must be what your referring to
Could we please not be stupid and only post when we actually have an idea about something, instead of remembering/believing incorrectly? (It's 63 for RU' and 105 for RU.)

Darn i was one off by one but yet i am so stupid. My life is ruined:eek:
 
While I understood that what miniGOINGS meant was that any alg, repeated enough times, will return the cube back to its initial position, but I also agree that he never mentioned that you were starting from a solved state, so his post sounded like he was implying any alg is the devil's alg, IF you take his post out of context.
 
Hello everyone. I'm new to the sight and a beginner at the rubix cube. I just started learning the F2L - Fridrich Method. I tried to search on the forums but was unsuccessful in finding the answer to my question.

Could someone plz point me in the right direction or post a few repeating algorithms that starts out with a solved cube and then ends with a solved cube?

I tried to search on the web, but all i see is videos and can't keep track with the movements. If it was posted earlier, I apologize, but didn't find them.

I'm looking for the algorithms if anyone has the time to post a few. Example - U R L U R L ...etc. Thanks

It's so that I can practice my finger movements and lubrication techniques easier.
 
first of all WELCOME
second, you just commited the worst crime evar (spelled Rubik's as rubix)
third. any move sequence repeated a certain number of times will solve the cube. R U R' U'x6 is a good example. if you want to practice finger tricks, i suggest just learning faster ways to do the algorithms you know. Youtube is a great recource learning moves you might not ever think of.
 
Yep, all algorithms repeated enough times will return to its original position.
If it didn't, then that would mean the rubik's cube has infinite positions, which it obviously doesn't.
 
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I also don't understand Stefan. He specifically says "will return" so we are assuming starting from a solved cube. He also mentions "original position" so he even covers the situation where it would go from "a U away from solved" to "a U away from solved again".

Otherwise it is easy enough to see: Start with a cube that is a U-move away from the scramble. Now repeat an alg like "R" and it will not return the cube back to solved ever although only 5 positions might exist ("solved", "U'", "U' R'", "U' R2" and "U' R")
 
What Stefan is saying is that, given that the cube has an algorithm that DOESN'T return it to the original state given enough iterations, that wouldn't necessarily mean that there are an infinite number of states of the cube. It could, for example, come to cycle between 3 states, where none of the three are the original state of the cube.
Correct me if I'm wrong, Stefan, but I believe that's what you're talking about.
 
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