Justin Barker, Learning EG-1 in 10 Days, and the Quest to Somehow Podium at OKCubing

Good luck.

Is 1 look with Ortega tough? In inspection you know the first face and PBL on the D layer. If you know how corners are permuted when you are doing your first face then you also know the OLL on top. Only pause is recognizing the PBL on U layer and then executing the alg however more experienced cubers will probably get that step in inspection as well.
 
Good luck.

Is 1 look with Ortega tough? In inspection you know the first face and PBL on the D layer. If you know how corners are permuted when you are doing your first face then you also know the OLL on top. Only pause is recognizing the PBL on U layer and then executing the alg however more experienced cubers will probably get that step in inspection as well.

I have never figured out how to one-look and it makes me so slow xD

also, on 3x3 I can't always see my first pair during inspection and it bugs me :(
 
Good luck.

Is 1 look with Ortega tough? In inspection you know the first face and PBL on the D layer. If you know how corners are permuted when you are doing your first face then you also know the OLL on top. Only pause is recognizing the PBL on U layer and then executing the alg however more experienced cubers will probably get that step in inspection as well.

its only a little harder than with full EG. Once you predict the OLL, all you have to do is find out whether U layer ends up solved, diag, or adj. so basically you have to know CLL recognition.
 
Are you using Chris Olson's website, that really helped me learn CLl and EG-1 because i match the case with its position on his site and it helps me a lot. the position doesnt change for other subsets either
 
EG-1 is 40 algs not 43 i dont know where yu got that. 6 sets have 6 and H has 4
And the OLL skip set, I don't know Ortega
Are you using Chris Olson's website, that really helped me learn CLl and EG-1 because i match the case with its position on his site and it helps me a lot. the position doesnt change for other subsets either
I was using AlgDB but I'll try.
Do you even know CLL yet?
Yes.
 
My site should be quite a bit better than what algdb has. I haven't checked algdb for 2x2 in a while, but last I checked it was missing a lot of good 2x2 algs. There's very few good algs mine is missing. Especially in EG-1.

*recommends own site*

That's a good point, and besides AlgDB bugs me because algs that should be together are separated; all of the EG algs on AlgDB are classified into separate pages by OLL case and it's rather annoying.
 
Yeah, you can get sub 3 with CLL, so my recommendation is to not learn EG -1 a few days before a comp. You need a lot of practice (talking weeks) to get used to those algs and use them fast. So practising CLL can get you faster, changing CLL algs if you need to is not a bad idea. I use CLL and am sub 3.5. Not sub 3 yet tho...
 
You might learnthem all in time but you should probably only use EG-1 in the comp if you can 1 look the solve, that lets you prepare. You probably wont be as fast with EG-1 as CLL by then
 
Alright, a bit of an update: I have the S and S' sets memorized, but 3 of my S' cases are a bit questionable (I have a hard time remembering which alg to use.) By the way, here's the code I use to create my super fancy images. It should be pretty self-explanatory, especially if you know how to code. It's in Processing. Processing is for nubs. Go ahead, use it (you won't probably no one will xD) I won't get mad just tell people I made it
Code:
static final String SET_NAME = "EG-1";
int[][] bySubset = { // { total, mastered, in-progress (number of algs learned but not well; it takes some thinking to remember which alg) }
  {6,6,0}, //S
  {6,3,3}, //S'
  {6,0,0}, //π
  {6,0,0}, //T
  {6,0,0}, //U
  {6,0,0}, //L
  {4,0,0}, //H
  {3,1,0} //O
};
String[] subsetNames = {
  "S",
  "S'",
  "π",
  "T",
  "U",
  "L",
  "H",
  "O"
};
int algsTotal = 0;
int algsMastered = 0;
int algsInProgress = 0;
void setup() {
  size(500, 500);
  for(int i = 0; i < bySubset.length; i++) {
    algsTotal += bySubset[i][0];
    algsMastered += bySubset[i][1];
    algsInProgress += bySubset[i][2];
  }
}
void draw() {
  background(0);
  noStroke();
  fill(255);
  textAlign(LEFT, TOP);
  textSize(20);
  text("Algs total: " + algsTotal, 2, 52);
  fill(255, 0, 0);
  rect(0, 0, width, 50);
  text("Algs left to learn: " + (algsTotal - algsMastered - algsInProgress), 2, 72);
  fill(255, 255, 0);
  rect(0, 0, map(algsMastered+algsInProgress, 0, algsTotal, 0, width), 50);
  text("Algs in-progress: " + algsInProgress, 2, 92);
  fill(0, 255, 0);
  rect(0, 0, map(algsMastered, 0, algsTotal, 0, width), 50);
  text("Algs mastered: " + algsMastered, 2, 112);
  fill(255);
  text("By Subset:", 2, 142);
  for(int i = 0; i < bySubset.length; i++) {
    fill(255);
    text(subsetNames[i] + ": " + bySubset[i][0] + " total, " + bySubset[i][1] + " mastered, " + bySubset[i][2] + " in-progress", 2, 162 + 20*i);
    fill(255, 0, 0);
    rect(370, 165 + 20*i, 100, 15);
    fill(255, 255, 0);
    rect(370, 165 + 20*i, map(bySubset[i][1]+bySubset[i][2], 0, bySubset[i][0], 0, 100), 15);
    fill(0, 255, 0);
    rect(370, 165 + 20*i, map(bySubset[i][1], 0, bySubset[i][0], 0, 100), 15);
  }
  fill(255);
  textSize(15);
  text("In-progress means learned but not learned very well.", 2, 182 + 20*bySubset.length);
  fill(0);
  textSize(40);
  text(SET_NAME + ": " + (float)round(1000*((float)(algsInProgress+algsMastered)/algsTotal))/10 + "% learned", 2, 5);
  save(SET_NAME + ".png");
}
 
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