I made a website with algorithms I use for Petrus & blindfolded solving

uXs

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As the thread title says, I made a site (actually just a single page), where I collected the algorithms I use for solving the cube.

You can find it here: http://users.telenet.be/uxs/rubik/

The main feature is that instead of using the standard notation, I use little pictures that show how to move. I find that I can read the algorithms much easier that way. I also added Java applets, because it makes it just a little bit easier to visualize what each algorithm does.

The complete solution isn't there, just the algorithms. For the complete solution, I refer to Lars Petrus' site for solving it with looking, and to the Cubefreak site for blindfolded.

I made it primarily for myself, but perhaps it can be of use to other people as well, which is why I posted the link here.
 
I know what the notation means, and I can read it very slowly. I just find it much much easier to read from pictures. (Or from fully written words, for that matter. I removed all the abbreviations like "UF" and "RB" in the descriptions yesterday because it reads faster.) It's all about having a quick reference in case of "what the hell was that algorithm again ?", and just being able to see the moves right away is nice. Call it a lot of effort now so I can be lazy later.

As for back turns, I just avoid having to do them by altering the algorithm. I can think of three where I did that:
-The algorithm to swap the upper corners crosswise in the blindfolded section
-"Bert" and "Arne" from step 7 in the Petrus method

In all three cases, I find the altered algorithm easier to memorize and easier to execute.

If you put a gun to my head and forced me to make a picture for back turns, I'd use the one for F-turns, but in a different color. Either inverted, or in red or something. I tried to make one a few days ago, but it looked kinda crappy.

I didn't make a converter. But it didn't take too long to do it all manually. Maybe if I need to encode a lot more algorithms, but I'm actually still learning to solve it blindfolded, which is taking all my time at the moment.
 
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