AvGalen
Premium Member
I might have the weirdest solves in here, but this is just my "style". Keyhole is my main method, but I am mixing in some regular F2L. And I don't know OLL PLL so I use 4 look last layer, but I try to avoid OLL's I don't know.
To summarize: 40 ("slow speedsolve"), 47 (slow speedsolve) and 51 ("Fridrich slow speedsolve")
Scramble1 (with cross color on bottom): U2 B2 R D L2 B’ R’ F D’ B2 R2 F’ D F2 D’ L’ R2 F’ D2 L B F2 D’ L’ R2
Using "optimal keyhole"
Cross (+ Edge 1) (5): L D F' B' L'
Corner 1 (+ Edge 2) (3): y' L' U2 L
Corner 2 (3): y L' U L
Edge 3 (3): R U R'
Corner 3 (7): y R2 U R2 U R2 U2 R2
Corner 4 + Edge 4 (4): y' D' L' U L
OLL (6): y R' U' F' U F R
PLL (9): y2 l' U R' D2 R U' R' D2 R2
"optimal keyhole means I go a bit slower and just do something in the F2L that solves something without breaking anything that is already done
This would have been a really nice solve for me
Scramble2 (with cross color on bottom): U B2 L B2 R2 B2 R' D2 L' U' L' B L B D L2 U L2 B2 L B' R' F D2 F
(how I would have solved it. It's a mixture between regular F2L (beginning), keyhole (middle part) and blindfolded (Last Layer))
Cross (5): B D' R L2 D'
1st pair (4): U2 R U R'
2nd pair (4): y' L F' L' F
3rd edge (3): y2 R U2 R'
3rd corner (+ 4th edge) (5): y' D2 U2 L' U' L
Corner 4: (7): y R2 U R2 U R2 U2 R2
Last Layer (19): z2 (R U R' U' R U R' U') D (U R U' R' U R U' R') U2 D
I also gave normal Fridrich a try:
Regular Fridrich
Cross (6): z2 y R' U F' U2 F' U'
1st pair (3): z2 y R U' R'
2nd pair (4): y' L F' L' F
3rd pair (7): R U' R' U R U R'
4th pair (4): y' L F' L' F2
OLL (5): R U R' U' F'
Corners PLL (10): U2 l' U R' D2 R U' R' D2 R2
Edge PLL (12): x' U R U' R U R U R U' R' U' R2
To summarize: 40 ("slow speedsolve"), 47 (slow speedsolve) and 51 ("Fridrich slow speedsolve")
Scramble1 (with cross color on bottom): U2 B2 R D L2 B’ R’ F D’ B2 R2 F’ D F2 D’ L’ R2 F’ D2 L B F2 D’ L’ R2
Using "optimal keyhole"
Cross (+ Edge 1) (5): L D F' B' L'
Corner 1 (+ Edge 2) (3): y' L' U2 L
Corner 2 (3): y L' U L
Edge 3 (3): R U R'
Corner 3 (7): y R2 U R2 U R2 U2 R2
Corner 4 + Edge 4 (4): y' D' L' U L
OLL (6): y R' U' F' U F R
PLL (9): y2 l' U R' D2 R U' R' D2 R2
"optimal keyhole means I go a bit slower and just do something in the F2L that solves something without breaking anything that is already done
This would have been a really nice solve for me
Scramble2 (with cross color on bottom): U B2 L B2 R2 B2 R' D2 L' U' L' B L B D L2 U L2 B2 L B' R' F D2 F
(how I would have solved it. It's a mixture between regular F2L (beginning), keyhole (middle part) and blindfolded (Last Layer))
Cross (5): B D' R L2 D'
1st pair (4): U2 R U R'
2nd pair (4): y' L F' L' F
3rd edge (3): y2 R U2 R'
3rd corner (+ 4th edge) (5): y' D2 U2 L' U' L
Corner 4: (7): y R2 U R2 U R2 U2 R2
Last Layer (19): z2 (R U R' U' R U R' U') D (U R U' R' U R U' R') U2 D
I also gave normal Fridrich a try:
Regular Fridrich
Cross (6): z2 y R' U F' U2 F' U'
1st pair (3): z2 y R U' R'
2nd pair (4): y' L F' L' F
3rd pair (7): R U' R' U R U R'
4th pair (4): y' L F' L' F2
OLL (5): R U R' U' F'
Corners PLL (10): U2 l' U R' D2 R U' R' D2 R2
Edge PLL (12): x' U R U' R U R U R U' R' U' R2