How to avoid the “long” parity algorithm for NxNxN

jyhjyi

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Sep 28, 2020
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JJ_Method
New method for NxNxN, without “long” parity algorithm and flipping algorithm .


step1: solve 6 centers
step2: pair 8 edges containing white and yellow
step3: solve white and yellow faces
step4: solve the lower half layers with ”cross layer commutator”
step5: solve the upper half layers with “self layer commutator “
step6: correct the centers(if necessary)
example
JJ Method step 4,5,6 example (8x8x8)(no parity errors)

step 4,5,6 walk through example (9x9x9)
JJ_Method#2

 
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When solving big cube11x11x11 or 17x17x17 …
there will be many times of flipping algorithm
and parity algorithm no more easily available.
JJ_Method can avoid them and will be faster
 
Last edited:
When solve big cube11x11x11 or 17x17x17 …
there will be many times of flipping algorithm
and parity algorithm no more easily available.
JJ_Method can avoid them and will be faster
ohhh yeah, I thought you were talking about 4x4 or WCA big cubes. Yes, this method will for sure help on those cubes
 
JJ_Method

step1: solve 6 centers
step2: pair 8 edges containing white and yellow
step3: solve white and yellow faces
step4: solve the lower-semi layers with ”cross layer commutator”
step5: solve the upper-semi layers with “self layer commutator “
step6: adjustment the centers(if necessary)
example JJ_Method#2
Technically, I don't think we are avoiding parity here.
 
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