I’m assuming it’s 12^18, there’s 12 combos for each clock, and 18 clocks, I don’t know enough about clock to be 100% sure on this, I would like some help on theirs.
I believe it would be 12^14 combinations. There are only 4 corner pieces - the corners on the front and back move together. This is of course not including different pin combinations, and it doesn't account for symmetrical cases.
I believe it would be 12^14 combinations. There are only 4 corner pieces - the corners on the front and back move together. This is of course not including different pin combinations, and it doesn't account for symmetrical cases.
I believe it would be (12^14)/2, as the original calculation allows for 2 symmetrical cases to each be counted. Since there are two sides, the amount of distinct cases are halved.
Apparently just 12^14. It's silly to include pins in the calculation as the pins are irrelevant to the solved state according to WCA guidelines. Symmetries do reduce the amount of states by a large factor.