How many algorithms have you learned?

How many 3x3x3 algorithms do you know?


  • Total voters
    216

Pretty ridiculous I know, I don't use all of these, but I have spent a lot of time researching/ figuring out new algs for every single case/angle. For instance, I know 5 ways how to solve case 24 alone x4 for all of the mirrors plus 1 for one case which I do something different for to avoid awkward L's and then add another 4 for when there are open slots. Thats 25 for a single case. Actually now that i come to think of it, the 237 DOESN'T include when I have open slots, I will have to recalculate.....

Jskyler: roux LSE 4? where? have you been learning some L5E or what?

I don't use Roux much, but I learned i think 4 cases for when you have the last 4 edges to permute.
 
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I don't use Roux much, but I learned i think 4 cases for when you have the last 4 edges to permute.

Yah just I personally don't count them as algs. I learn em intuitively and they are only 4 moves long...

Also F2L I also believe you're exaggerating- where did you get that exact number 237 from? Even if you do consider the intuitive F2L cases algs, that's still far from 237.
 
Yah just I personally don't count them as algs. I learn em intuitively and they are only 4 moves long...

Also F2L I also believe you're exaggerating- where did you get that exact number 237 from? Even if you do consider the intuitive F2L cases algs, that's still far from 237.

I went through and counted them real quick, The cases I consider intuitive and execute as such are: 1, 4, 5, 7, 9, 10 & 19 and i still know about 2-3 ways to solve each of them algorithmically, although I don't use them. The rest of them I know about 2-3 different algs for each of the 4 angles (Some less some a lot more). For some of them I know a crazy lot more as I said above and others only 1 way. Then if you count when there are open slots, that adds quite a few more. I might be off by like 3 or 4 due to miscounting, but this amount is not really exaggerating at all.

I actually forgot 1 for the cross so it is actually 6 and they are for a single edge piece flipped in place on the right: Ru'Ru and the same on the left (not at all intuitive to me.), 2 Edge pieces flipped in place in the front and front right slot slot: DRD2F'DR'F2 (i don't do the left hand version), two adjacent edges needing to switch in front right RDR'D'R and the same for the left, and finally, not sure how to describe this, but just do the inverse to see what I am talking about R'DRD2R'.

EDIT: Do you guys honestly think I would lie? What would I have to gain from that?

EDIT 2: Btw when I say not intuitive i mean that I use not intuitive ways of solving them, not that they can't be solved intuitively.
 
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Not at all. Everyone just thinks it's silly that you count F2L and cross as 'algs', especially adding mirrors etc. No one else really does that.

The question in the poll and in the thread was "how many 3x3x3 algs do you know?" I was simply answering that as thoroughly as I could. A left hand sune is a different alg from that of a right hand sune and so are each of the 4 angles, plus if you watch my F2L videos I often execute things completely differently from the back two slots than the front two. Each of these cases are distinct algs and so I listed them as such. I actually did this to avoid people saying that I was exaggerating and then asking me to list how I can up with my number so I figured I would do this instead. I guess I am just doomed to be overly explicative on this forum.

EDIT: I love how Aronpm put up >850 algs and not a single person questioned him lol.
 
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I don't count F2L cases, because I do F2L intuitively... Although f2l is now like algs because I don't have to think anymore, it still doesn't count. I included OLL, PLL, (including multiple algs for dif cases [OH, skips, etc]; big cube parity I counted 2 - Lewis (?) parity and beginner, because the algs are the same for 4x4, 5x5, 6x, 7x7, 8x8, 9x9, 10x10, etc, etc; SQ1 counts beginner stuff, algs I made up myself for my method that I figured out, both parities, etc; pyra counted L3E cases; megaminx I didn't say because my algs are the same as I use for 3x3, just slightly modified. If I add in BLD algs (TuRBo edge algs not already used in OLL) and various non standard cube algs (curvy copter, rex cube, cuboids, etc) I get 105

EDIT: O WAIT1!1!!!1 Only 3x3? hehe
OLL: 57 + 7 (COLL stuff) = 64
PLL: 21 + 6 (other algs i use depending on AUF) = 27, + 64 = 91

Whew... Still in the 90+ group lol so I still voted properly. Now that I'm looking at that, I'm thinking my algs for other cubes are more than 14... oh well...
 
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I don't count F2L cases, because I do F2L intuitively... Although f2l is now like algs because I don't have to think anymore, it still doesn't count. I included OLL, PLL, (including multiple algs for dif cases [OH, skips, etc]; big cube parity I counted 2 - Lewis (?) parity and beginner, because the algs are the same for 4x4, 5x5, 6x, 7x7, 8x8, 9x9, 10x10, etc, etc; SQ1 counts beginner stuff, algs I made up myself for my method that I figured out, both parities, etc; pyra counted L3E cases; megaminx I didn't say because my algs are the same as I use for 3x3, just slightly modified. If I add in BLD algs (TuRBo edge algs not already used in OLL) and various non standard cube algs (curvy copter, rex cube, cuboids, etc) I get 105

I do most of f2l algorithmically.
 
EDIT: I love how aronpm put up >850 algs and not a single person questioned him lol.
I just assumed that he counted all the BLD cases that you make up algorithms for on the spot.

I think I know in the 50-59 area, but probably in the 60's with some miscellaneous algorithms I'm forgetting.
 
A left hand sune is a different alg from that of a right hand sune and so are each of the 4 angles etc

I entirely disagree. This definition of 'algorithm' in the context of 'uniqueness'... It basically is meaningless because, at least from my perspective, I would know at least twice as many 'algs' as I reckon I do, simply because my overall execution style has changed a few times.

You could also argue that every time you learn one alg you actually learn 12 because of all the different angles and mirrors you should be able to use them at, then inverses makes 24.

Imo, number of algs should be concerned with distinct operations (I know this is quite a fuzzy thing to distinguish). R U2 R2 F R F' R U2 R' on 2x2 and r U2 R2 F R F' R U2 r' on 3x3 are the same alg.

Intuitive conjugations like this should be counted as one, meaning that OLL can be done using one algorithm, but with 31 different conjugations (plus mirrors).
 
total: 265
Hmm, I think I can add on another 300 or so (including non-3x3 algs).

For just 3x3x3, let's see...
F2L: idk...100? Depends on the definition of an alg, but I learned almost all of it algorithmically, so I'll count those ones.
OLL: ~150 (2 or 3 algs per case on average)
PLL: ~ 70 (3 or 4 algs per case on average)
CxLL: ~50 (excluding the overlap with OLL)
ELL: ~15 (excluding the overlap with OLL)
CPEOLL: 10 (excluding the overlap with ELL)
LS stuff: ~40? (including VHLS, WV, Magic Wondeful etc.)
Misc. Comms: ~15 (lol)

So, over 400 I guess.
 
The question in the poll and in the thread was "how many 3x3x3 algs do you know?"

Most people don't consider trivial things like Ru'Ru seperate algs. Maybe you do, but that makes your results incomparable to other people.

EDIT: I love how Aronpm put up >850 algs and not a single person questioned him lol.

It was a joke;

<+aronpm> i just want to say i know more algs than i do
 
Earlier I said 15, but that was a rough estimate just for 3x3. Now for an actual count.

Ortega - 12
Other CF algs - 2
H-perm
Clockwise Edge 3-cycle
4x4 parities - 2
SQ-1 algs - 4
3x3x4 algs - 3
Pyraminx algs- 2

So about 27.
 
Well... Full CFOP, with about 10 F2L algs, almost 80 OLLs and 50 PLLs, 2x2 ortega, some CLL algs, 4x4 and 5x5 parities, BF algs...

250 probably.
 
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