Help with being sub5 at 2x2x2

[PoHos1]

hallo all I am new with 2x2 cube .. please how can I be sub5 I konw that CLL metod is best but how many algoritms I must can to be sub5 and how can i get good lookahead

 

[emolover]

Use Ortega, it has 7 algs and is easy to learn.

Sub 5 is very easy with it, myself have a sub 3 average of 50 with it.

 

[tx789]

Learn Ortega CLL has 42 algs and recognition takes time to get used to

 

[Petro Leum]

Learn Ortega CLL has 42 algs and recognition takes time to get used to

i found CLL recognition easier to get used to than ortega.
nervertheless Ortega is a reaaaally good method to start with for 2x2.

 

[yoshinator]

Use Ortega, it has 7 algs and is easy to learn.

Sub 5 is very easy with it, myself have a sub 3 average of 50 with it.

Sub-3? Do you always predict OLL? Are you using SS? I'm so impressed.

 

[emolover]

Sub-3? Do you always predict OLL? Are you using SS? I'm so impressed.

I do always predict the OLL and if that was easy I try to predict the PBLL(I already know what it is on the bottom). I don't use SS but it would be very nice to learn, I do it intuitively sometimes.

Ortega is way too underscored for what it is. You don't have to learn an EG approach to do well. SOAP, SS, OFOTA, and OSPA can create fast times too.

BTW there was a typo in my original post, it should be 10 algs.

 

[nqwe]

i found CLL recognition easier to get used to than ortega.
nervertheless Ortega is a reaaaally good method to start with for 2x2.

Just because you are using COLL

 

[PoHos1]

Use Ortega, it has 7 algs and is easy to learn.

Sub 5 is very easy with it, myself have a sub 3 average of 50 with it.

wtx so mutch I can all algoritms so.. now practise thx

 

[Zarxrax]

Sub-5 is "very easy"?
Maybe a bit of an understatement.
Sub 5 may be possible with tons of practice, but I definitely wouldn't say "very easy".

I've been practicing ortega for years, probably well over 10,000 solves, and I still struggle to be sub-6 consistently.
I'm slow and crappy though.
But less than 10% of WCA competitors have achieved sub-5 averages with any method.
So sub-5 is definitely something that takes some serious work, IMO.

 

[emolover]

I think sub 5 can be possible in as little as 3000 solves.