[Unofficial] Dylan Miller 3.96 3x3 Mo3

[An Animating Cuber]

2 LL skips in a row followed by a PLL skip

(Mo3 ends at 47:38)

 

[siwoo]

I've seen enough, getting lucky is a crime.

 

[AJT17]

2 LL skips in a row followed by a PLL skip

(Mo3 ends at 47:38)

Is this the quickest stackmat mo3? I know Kyle got a 3.25 mo3 on keyboard but that doesn't count and I am not aware of any other sub 4 mo3's.

 

[Bingus cuber]

What are the odds of 2 LL skips in a row???? And then a Pll skip, this is stupid.

 

[SkewbIsTheBestEvent]

What are the odds of 2 LL skips in a row???? And then a Pll skip, this is stupid.

I believe it is 1/17414258688 when thinking about 2 ll skips in a row + a pll skip, which is 1 out of 17 billion.

This is unbelievable, definitely cheating (jk)

 

[That_slow_guy]

 

[Spencer131]

I believe it is 1/17414258688 when thinking about 2 ll skips in a row + a pll skip, which is 1 out of 17 billion.

I'm curious how you got that?

If the odds of a last layer skip is 1/15552 then I think 2 in a row is 1/241864704 (basically the original number squared). Not completely sure tho

 

[JDAW6]

2 LL skips in a row followed by a PLL skip

(Mo3 ends at 47:38)

I know we shouldn’t get hasty but this is a bit sus.

 

[siwoo]

I know we shouldn’t get hasty but this is a bit sus.

It's not sus at all when it's 40 minutes into a livestream with his entire CsTimer setting showing that it's normal. Plus he has over 30000 solves in that session, so why would be jeopardize all his legitimate solves for 2 fake last layer skips ???

 

[SkewbIsTheBestEvent]

I'm curious how you got that?

If the odds of a last layer skip is 1/15552 then I think 2 in a row is 1/241864704 (basically the original number squared). Not completely sure tho

I multiplied that by the pll skip he got

 

[Discomantis]

I believe it is 1/17414258688 when thinking about 2 ll skips in a row + a pll skip, which is 1 out of 17 billion.

This is unbelievable, definitely cheating (jk)

If you count the fact that the first LL skip that Dylan had ended up having no AUF, the number actually becomes 1/69,657,034,752 or one in 69 billion.

 

[JDAW6]

If you count the fact that the first LL skip that Dylan had ended up having no AUF, the number actually becomes 1/69,657,034,752 or one in 69 billion.

Nice

 

[Ordway Persyn]

I believe it is 1/17414258688 when thinking about 2 ll skips in a row + a pll skip, which is 1 out of 17 billion.

This is unbelievable, definitely cheating (jk)

Dylan does do edge control on many solves so the chances of him getting a LL skip is less than that.

 

[JDAW6]

Dylan does do edge control on many solves so the chances of him getting a LL skip is less than that.

Woaj I didnt know that other people also do edge control a lot like me. I thought edge control was just useless till now.

 

[abunickabhi]

Insane yo, super unlikely 3 solves in a row.

Getting lucky is not a crime.