5BLD and PandaCuber's Roux tutorial

your DR first centric thinking lets you forget that you can leave the FR square floating R' away ZZ style

Read the post above yours again... do you get what I am trying to say? It's about ensuring you're at least not guaranteed not optimal. You can leave it floating if you want but thats not the point... As for me being DR centric, well thats why I am doing these exercises- to stop me thinking like this. If it makes you feel better whatever, I don't care as long as counting my way it is under 10 moves. You can still leave out the last move if it matters so much.

next: D2 L2 F2 L2 U2 L2 B U2 R2 B F2 L B' R' D R' U' R D2 F R2
yx'R2B'
 
next: D2 L2 F2 L2 U2 L2 B U2 R2 B F2 L B' R' D R' U' R D2 F R2
yx'R2B'

Are you sure it's y x' R2 B'?
I can't see a square formed when I do those moves.
Maybe it's y' x' R2 B'? (A Yellow-Blue-Red square is formed.)

My solution:
y' x' R2 B'

U R2 U' F R' M' U' F2 U F' (R) (11 or 10)
 
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Why call it ZZ style? Isn't building this square just as much Roux as it is ZZ?

Sure. I called it ZZ style as the majority of cubers use CFOP, and that is a key difference in the F2L style of ZZ compared to CFOP. Was calling it that for clarity.

Read the post above yours again... do you get what I am trying to say? It's about ensuring you're at least not guaranteed not optimal. You can leave it floating if you want but thats not the point...

I wasn't replying to your post. I was making a comment in general.

If it makes you feel better whatever, I don't care as long as counting my way it is under 10 moves. You can still leave out the last move if it matters so much.

Calm down baby, our relationship can't blossom if you're always jumping to conclusions like this </3.
 
7 for block + square

y x' R2 B'
F' U F R2 F' U' F2 - 7

U' M2 U' R' M' F' R U M2 leaves 3C 3E for a 33HTM final result :)

I had that start. But technically you can't because I said rest of FB and first square of SB. But I don't care. Awesome solution.


F2 U' R' U' R U' R2 U' F' 9 (9)

elegent indeed. found by trial and error? if not how did you find it?
 
elegent indeed. found by trial and error? if not how did you find it?
The SB-pair already is build and in F. The idea is to create the FB-pair without destroying SB-pair and insert both pairs simultanous using F'.
F2 moves SB-pair in the correct position and will let you build the FB-pair RU-gen without destroying the SB-pair. U' R' U' R creates the FB-pair. U' R2 solves the DR edge and U' F' finally inserts both pairs.
 
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