4x4 reduction

[Zarxrax]

I am trying to learn the reduction method for 4x4. I got the centers all matched up, and I've paired up all of the edges except 2 pairs. I can't figure out how to solve these last 2 pairs though, because if I solve one pair, then I end up having to separate an already solved pair.

 

[EmersonHerrmann]

Make it so the two pairs are across from each other (also, put the same edges across from each other). Then do this alg:

Uw' R F' U R' F Uw

 

[qqwref]

I saw someone in competition once who solved those with a *parity alg* (the one that swaps UFl and UBl). I had a hard time not telling him not to do that during the solve.

But yeah, do what Emerson said. (Place the edges at FR and FL.)

 

[chimpzi]

Make it so the two pairs are across from each other (also, put the same edges across from each other). Then do this alg:

Uw' R F' U R' F Uw

or you could do this:
there will only be two cases, either they are across with each other or opposite with each other. if you dont want to set it up, you can use this alg:

opposite with each other: dw [R U R' F R' F' R] dw'
across with each other: L2 dw2 [R U R' F R' F' R] dw2 L2 (i think the last L2 is not necessary..is it?)

*i dont actually memorize the alg..let me know if the alg works or not..

thanks.
more power.

 

[Neutrals01]

Make it so the two pairs are across from each other (also, put the same edges across from each other). Then do this alg:

Uw' R F' U R' F Uw

or you could do this:
there will only be two cases, either they are across with each other or opposite with each other. if you dont want to set it up, you can use this alg:

opposite with each other: dw [R U R' F R' F' R] dw'
across with each other: L2 dw2 [R U R' F R' F' R] dw2 L2 (i think the last L2 is not necessary..is it?)

*i dont actually memorize the alg..let me know if the alg works or not..

thanks.
more power.

wow...thanks for the across with each other algo....save 3 moves for me

 

[AvGalen]

Make it so the two pairs are across from each other (also, put the same edges across from each other). Then do this alg:

Uw' R F' U R' F Uw

or you could do this:
there will only be two cases, either they are across with each other or opposite with each other. if you dont want to set it up, you can use this alg:

opposite with each other: dw [R U R' F R' F' R] dw'
across with each other: L2 dw2 [R U R' F R' F' R] dw2 L2 (i think the last L2 is not necessary..is it?)

*i dont actually memorize the alg..let me know if the alg works or not..

thanks.
more power.

wow...thanks for the across with each other algo....save 3 moves for me

Instead of [R U R' F R' F' R] I prefer [R U' R' F' U2 F]
Instead of L2 dw2 [R U R' F R' F' R] dw2 L2 I prefer to do R2 instead of L2

 

[Zarxrax]

Lol doing these algorithms is messing up all my matched pairs.
- Am I supposed to be holding it with the pairs on the top layer?
- Does dw mean turn the bottom 2 layers?
- I'm not sure I understand the difference between opposite one another and across from one another. In this diagram, are the ones and twos "opposite" each other?

****
1**2
2**1
****

 

[qqwref]

Hold it like this (this is the F face)
****
1**1
2**2
****
and do Uw' R F' U R' F Uw

 

[chimpzi]

Make it so the two pairs are across from each other (also, put the same edges across from each other). Then do this alg:

Uw' R F' U R' F Uw

or you could do this:
there will only be two cases, either they are across with each other or opposite with each other. if you dont want to set it up, you can use this alg:

opposite with each other: dw [R U R' F R' F' R] dw'
across with each other: L2 dw2 [R U R' F R' F' R] dw2 L2 (i think the last L2 is not necessary..is it?)

*i dont actually memorize the alg..let me know if the alg works or not..

thanks.
more power.

wow...thanks for the across with each other algo....save 3 moves for me

Instead of [R U R' F R' F' R] I prefer [R U' R' F' U2 F]
Instead of L2 dw2 [R U R' F R' F' R] dw2 L2 I prefer to do R2 instead of L2

never thought of that..haha
thanks..

Lol doing these algorithms is messing up all my matched pairs.
- Am I supposed to be holding it with the pairs on the top layer?
- Does dw mean turn the bottom 2 layers?
- I'm not sure I understand the difference between opposite one another and across from one another. In this diagram, are the ones and twos "opposite" each other?

****
1**2
2**1
****

1**1
2**2
this is opposite..

1**2
2**1
this is across..

[based on my interpretation]


and yes, the pieces must be on F face..
again, yes.. dw turns the two D layers...

 

[Zarxrax]

Oh ok, I was holding it with the pairs on the top face.

 

[chimpzi]

Make it so the two pairs are across from each other (also, put the same edges across from each other). Then do this alg:

Uw' R F' U R' F Uw

or you could do this:
there will only be two cases, either they are across with each other or opposite with each other. if you dont want to set it up, you can use this alg:

opposite with each other: dw [R U R' F R' F' R] dw'
across with each other: L2 dw2 [R U R' F R' F' R] dw2 L2 (i think the last L2 is not necessary..is it?)

*i dont actually memorize the alg..let me know if the alg works or not..

thanks.
more power.

wow...thanks for the across with each other algo....save 3 moves for me

Instead of [R U R' F R' F' R] I prefer [R U' R' F' U2 F]
Instead of L2 dw2 [R U R' F R' F' R] dw2 L2 I prefer to do R2 instead of L2

i tried R2 instead of L2 but it does work..:confused:
i think it pairs the two back dedges or the left back dedge with right front dedges. i forgot.

so instead, i used L2 then uw2.. its easier than dw2[for me]..