2 step finish for Roux Edges

LOL, when I tried a number of diffrent styles and timed the results I found the fastest way for me to solve L6E was to just compleate F2L and then do ELL :P

It makes a pure 2-look, you can erasily see how to solve centres and BD+FD in one look. Recog for ELL can be slow and some algs are terrible but it is still fast becuse you only stop once.

Another method:

1; pair up UR and UL in D and then palce them in correct position.
2; EML, edges of middle layer, usally in 2 looks.

2a; simply use U2 M moves to solve one of the oriented edges if any. 4-flip is bad but that only happens 1:8 times. If it does you have to use a 3-cycle or a pure flip also for the first look (or learn all 4 algs you need for one look if it is 4-flip, I'm currently looking for them =))
2b; solve what's left, either a 3-cycle or a 2-flip.

In 1:8 you skip EO and have the usual Roux end after step 1.

Really smooth actually =)

3-cycles:

U2 M' U2 M / M' U2 M U2
U M' U M' U2 M U M (or mirror)
(y) U M U' R2 U M' U' R2
(y) R2 U M U' R2 U M' U'

Edit : 4-flip (not pure) is 11 STM optimal:

(U F2 U2 M' U) M2 (U F2 U2 M' U) (11f*) (E perm)

More edit: got a pure in the same length:

(F U2 F2 M F) M2 (F U2 F2 M F) (11f*) (pure)

(F U2 F2 M F') M2 (F' U2 F2 M F) (11f*) (x perm)

The last case (3-cycle 1-flip) is bad, it takes 16 MU optimally. Use a 2-flip on the permuted edge and one more and you have a 3-cycle.

Optimal face: R F' D' F2 B' R' U F U' F2 B D R' F (14f*) ... hmm, :P
Optimal MU: M' U' M U' M' U' M U' M' U M' U M U' M U' (16,16) ... q-moves!
Optimal R2/Rw2 MU: M' U' (R2 M') U' M' U Rw2 U R2 U' M' U Rw2 (14s, 13a) ... better.
Optimal F2 MU: F2 U M2 U M' U2 F2 M2 U' F2 M F2 U (13,20) ... works but Rw is faster I think.

There is no shortage of possible methods for solving LSE. The point of the method I posted as to have a solid 2 look LSE without overloading on the number of algorithms. In this sense, it is better than solving DF and DB, then ELL, as there are fewer algorithms to learn.

Any other method that takes 3 steps would have to have a significantly lower move count than Roux's original method, or be equally fast to be worthwhile. His method seems to be freakishly fast with very few, very simple algorithms.
 
Any opinions on this (partial) strategy for the Roux edges:

1. If all the top edges are good, do an M2. Now if all the edges are still good, you're done, but if you have 2 bad edges, do MUM'U'MUM(').
2. If you have two bad edges on top that are situated opposite of each other, look at the bottom. If the bottom is all good, make sure the bad edges on top are in the UF and UB positions and do MUM'U'MUM('). If the bottom has 2 bad edges, make sure the bad edges on top are in the UL and UR positions and do F2M'F2U'M(').
3. If you have 4 bad edges on top and 2 good ones on the bottom, do M2F2M'F2U'M(').
4. If you have 6 bad edges, do LF'L'U'MULFR'.

This only addresses those cases that I found difficult without algs. The other cases I do intuitively. The above really just contains 3 easy algs, and I find that they help a lot and aren't that horrible to execute.
 
Any opinions on this (partial) strategy for the Roux edges:

1. If all the top edges are good, do an M2. Now if all the edges are still good, you're done, but if you have 2 bad edges, do MUM'U'MUM(').
2. If you have two bad edges on top that are situated opposite of each other, look at the bottom. If the bottom is all good, make sure the bad edges on top are in the UF and UB positions and do MUM'U'MUM('). If the bottom has 2 bad edges, make sure the bad edges on top are in the UL and UR positions and do F2M'F2U'M(').
3. If you have 4 bad edges on top and 2 good ones on the bottom, do M2F2M'F2U'M(').
4. If you have 6 bad edges, do LF'L'U'MULFR'.

This only addresses those cases that I found difficult without algs. The other cases I do intuitively. The above really just contains 3 easy algs, and I find that they help a lot and aren't that horrible to execute.

don't use F moves to solve eo, it's a lot harder to fingertrick. and you seem to have a hard time figuring out what the orientation of the bottom edges are. believe it or not, just from being able to see the top and the FD color, you will know all the orientations of all the edges. know that there is always an even number of bad and good edges and use the FD color to deduce the orientation of the FD edge as well as the BD edge.
 
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