2 DIFFERENT PLL'S?

[MAGIK]

idk y or how but i had a weird situation with my cube....i had to to do a J perm and then do R U' R U R U R U' R' U' R2 to switch my edges counterclockwise.....is this even possible to have to do two permutations to solve it?

 

[deco122392]

no unless you employ a 2lpll other wise itd just be 1 of the 21 cases (concidering your ll is oriented and your not doing crazzy 1lll but then again you wouldnt be cuz ur using pll )

 

[trying-to-speedcube...]

Nope, what you had is an R-perm (I think). Maybe you don't know the R-perm yet, but there is an algorithm for it.

R' U2 R U2 R' F R U R' U' R' F' R2 U'

edit: 100th post!! yay!

who cares...

 

[MAGIK]

no unless you employ a 2lpll other wise itd just be 1 of the 21 cases (concidering your ll is oriented and your not doing crazzy 1lll but then again you wouldnt be cuz ur using pll )

i know thats what i sed i mean i dont know how that could be if im doing pll....it should always be one of those 21 cases am i right?

 

[brunson]

You did the wrong PLL. As Trying-to-speedcube pointed out, you didn't have a J, you had an R. If you perform a J algorithm on an R case you end up with an A perm.

 

[cuBerBruce]

Or he could have had a J-Perm, but executed the wrong J-Perm.

 

[trying-to-speedcube...]

You did the wrong PLL. As Trying-to-speedcube pointed out, you didn't have a J, you had an R. If you perform a J algorithm on an R case you end up with an A perm.

You can call me Maarten.

He ended up with a U-perm, not an A-perm.

 

[brunson]

Yeah, you guys are right. I read his second alg wrong. Anyway, in answer to the question. No, there are no PLLs other than the standard 21. You just did the wrong alg.