Sweet solve, very efficient F2L. Pairs! Pairs! I got your CE pairs right here! =)
B2 U2 F D2 B' L2 F D' B D2 B F' D' F' R2 D' U' R B'
x2 // inspection
R' U x U' R z' // cross (+2)
U' R U z' U' R U' R' // 1st pair (+1)
U' y R U' R' // 2nd pair (+1)
y U2' R' U R U' R' U' R // 3rd pair (+2)
U U' (y z) U' R U z' // 4th pair (+2)
U3' x' R U2' z U' R' U z' U' R' x // OLL (+7)
U2' R2 U' R' U' R U R U R U' R U' // PLL (+2) alg.garron