Interesting way to solve the problem.
3³ is corner orientation case. 4!² is corner and edge permutation. We have to divide by 2 for parity and 4 for equivalent cases modulo U move.
So we have 1944 states for ZBLL.
Standard cases are T, U, S, Ssym, Pi, L orientation case and regroup 24 case on 27. Each case in this category can occur in 4 different direction so each are 4 / 1944 = 1 / 486 .
These case occurs 4*432 / 1944 = 1728 / 1944.
PLL are categorized as follow (pll and his symmetry are equivalent in term of probability) :
type A : A, T, F, G, J, R, U, Y, V .
type B : Z, E .
type C : H, N, skip.
Type A can occur in 4 different directions and have a probability of 4 / 1944 = 1/486 .
Type B can occur in 2 different directions and have a probability of 2 / 1944 = 1/972 .
Type C can occur in 1 direction and have a probability of 1 / 1944 .
PLL occurs (4*16 + 2*2 + 3) / 1944 = 71 / 1944 and skip 1 / 1944 .
H orientation is the most complex one.In this orientation :
Type A occur in 4 different directions in 2 different cases with a probability of 4 / 1944 = 1 / 486 .
Type B occur in 2 different directions in 2 different cases with a probability of 2 / 1944 = 1 / 972.
Type C occur in 2 different directions in 1 different cases with a probability of 2 / 1944 = 1 / 972.
The H case probability is (4*2*16 + 2*2*2 + 4*2) / 1944 = 144 / 1944 .
I think I got the solution now
