Faster N Permutations

N is so funny. So many people hate their algorithm, and I'm not particularly fond of mine, but everyone just seems to suck it up. I do a very typical alg that I'm pretty sure I got from Macky's page, but I changed it by flipping U to L or R. That allows me to do what would normally be L and R are U and D, which I can do with LH first and ring fingers while gripping the cube with my LH on E, all the while RH is doing R, R' and R2. It's not the greatest, but it works for me.

Bob Burton's comment on one of his alg's is simple, "this alg blows."


I'd really be interested to hear from anyone that is pleased with their N.
 
For N:a I use this: (RUR'U) (J:b perm) (U'RU'R'). My J:b perm is (RUR'F') (RUR'U'R'F) (R2U'R'U'). It's rather long, but is easy and flows nicely. I hate D and B moves, so this fits my style. For N:b, I use (R'URU') (R'F'U'FRU) (R'FR'F'RU'R).
-- Auburn
 
i like my N
(R U' R' U) (l U F) U' (R' F' R U' R U l' U R')
but surely you've already found this one, so I dunno what to tell you
 
I don't understand how Nakajima gets his Ns so fast...I think the key is in his Z axis turn or r axis turn in japanese notation

Someone needs to make a fingertrick video...
 
did you guys try this one?

i do not know if this algorithm is for Na or Nb
but just try it

R U R' (u) R U2 R' U' R U2 L' U R' U' L (u') R U' R'

the idea is very simple
is just to set up the cube in order to solve N pll as a L pll
so for the other way, you just have to start like R' U' R and apply the other L (normally called J) pll

any questions, ask, and i'll be pleased of answering
 
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did you guys try this one?

i do not know if this algorithm is for Na or Nb
but just try it

R U R' (u) R U2 R' U' R U2 L' U R' U' L (u) R U' R'

the idea is very simple
is just to set up the cube in order to solve N pll as a L pll
so for the other way, you just have to start like R' U' R and apply the other L pll

any questions, ask, and i'll be pleased of answering

Isn't it Called J-Perm...?
 
Thank you NicoJ !!

I kind of like those. I've been putting off learning the Ns, as they are the last PLLs that I do not have memorized and I don't like any of the ones that I have tried.

I just ran through these a few times and they are very easy to remember, since they have the embedded J (or L as you said) PLLs. I'm not super fast with them, but they work, and are certainly faster than doing a Y perm followed by a U perm, which is what I've been doing instead.

So how did you figure that out? I can't see the J permutation at all in the middle. I'm very curious how you came up with this idea.

Brian.
 
So I've been playing with NicoJ's idea and drilled the Ns like crazy with this method and I liked my results.

Just a few minutes ago, I decided to actually look at the blocks during the (R U R' u) setup and, amazingly enough, I actually see how the blocks have been moved into a J perm.

So I asked myself, why is the last setup move a (u) instead of a simple (U) ?

I couldn't see a reason, so I tried it out. It works with a setup of (R U R' U) just as well. Obviously, the "unsetup" (commutator?) now must become: (U' R U' R')

This has an interesting consequence for me in both of the N perms due to the type of J perms that I use. Specifically:

J1: (R U R' F') (R U R' U') (R' F R2 U' R' U')
J2: (L' U' L F) (L' U' L U) (L F' L2 U L U)

So now putting it together:

N1 = R' U' R U + J2 + U' R' U R

Notice that J2 ends with (U), but the next move in the sequence is U' . So they cancel out, making the alg shorter. Altogether:

N1: (R' U' R U) (L' U' L F) (L' U' L U) (L F' L2 U L) (R' U R)

N2 is similar in that J1 ends with U' and the next move in the sequence is another U' , which yields a U2. Altogether:

N2: (R U R' U) (R U R' F') (R U R' U') (R' F R2 U' R') U2 (R U' R')

These are long, but because they contain so many triggers, and of course the familiar Js, they are reasonably fast, at least by my slow standards.

This is great for me since I have never found any Ns that I liked previously and thus had put off learning them. Give these a try and you might find you like them as much as I do.

Brian.
 
So I asked myself, why is the last setup move a (u) instead of a simple (U) ?
(u) = y

Well that's irritating. I can understand when notations are different, for example having Uw meaning the same thing as u . But now the modifier is a set of parenthesis? Oh well, I guess I'll learn these as I go along. I was simply trying to offset a single letter of notation in the middle of my sentence. I hadn't even realized that NicoJ had done it and had meant y when he typed (u) .

It's an interesting coincidence that both methods work and that my analysis still holds true. So the question becomes, what would you rather do: Rotate the cube a quarter turn, or turn the U face a quarter turn? I know my answer. :)

...oh and I still thank NicoJ for this. This is awesome. :)

Brian.
 
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