Remember the letters in groups of fours. For example
A G H F
You would do the inverse algorithm on the 2nd and 4th one.
X R E B
Again, you would do the inverse algorithm on R and B.
That's an explanation I hardly understand, and I use the method! Shame on you!
Ok, so you probably memorise with DF as buffer (with the D sticker as start of the cycle), shooting to UB with M2. There are only 4 special cases. Notice that shooting to UB of BU is not really a special case, and the alg will always be the same, either M2, or something that does the same AND also flip the 2 involved edges. For the DB, BD, FU and UF targets however, the algs will be different, depending on whether the centers are 'solved' or not.
So there are 4 algs that are kinda special:
Shooting to UF: U2 M' U2 M'
Shooting to FU: F E RUR' E' RUR' F M2
Important observations to make:
Both algorithms will keep the UB edge unchanged. The DB edge will remain between the same centers, but it will end up at UF (because of the M2, ofcourse).
Shooting to DB: M U2 M U2
Shooting to BD: M2 D R' U R' U' r R' U R U' r' R2 D'
Important observations to make:
Both algorithms will keep the UB edge unchanged. The UF edge will remain between the same centers, but it will end up at DB (because of the M2, ofcourse).
Now, memorisation of the targets is the same as old pochmann. I recommend memorising in pairs (pairs of targets, possibly converted into letterpairs). When you have UF as a target, and it's the first letter of a pair, you know the centers will be in 'correct' position, and you can use the regular alg for UF (U2 M' U2 M'). When it's UF and it's the second letter of a pair, you know the centers will be 'incorrect', and therefore you have to shoot to DB rather than UF, so you use M U2 M U2.
Example 1:
Setup with D' L2 M2 U M U2 M' U M2 L2 D
Memo: First target is UR, second target is UF.
Solution:
First target(UR): R' U R U' M2 U R' U' R.
For the second target, UF would be the second member of a letter pair. That means the centers are not in their positions, so we have to shoot to DB rather than UF: M U2 M U2.
Example 2:
Setup with D' L2 M2 U' M U2 M' U' M2 L2 D
Memo: First target is UF, second target is UR.
Solution:
First target is UF, and since it's going to be the first member of a letter-pair, we know that the centers are correct, and we can use the regular alg for UF: U2 M' U2 M'. Notice how the 'solved' edge ends up at DB, but between the correct centers.
Second target(UR): R' U R U' M2 U R' U' R.
It might be hard to get used to, but when you memorise in pairs, you don't have to keep track of the centers. You just need to consider if the centers are correct when you run into one of the 4 special cases.
I hope this helps.
