Blindsolving Accomplishment Thread

Single? Absolutely. A sub-1 average might be tough, though.

Consider that:
1. I have a pretty bad clock. Actually, it's good, except that one of the dials is messed up and doesn't turn smoothly, which can be deadly for BLD. (I should mention that this is Joey's clock, and I am tremendously grateful for it. It's not his fault that it's bad - when he sent it to me it was perfect. But I dropped it about a year after he sent it to me, and it's never been the same. :()
2. I'm really pretty bad at clock anyway - I average around 17 or 18 seconds solving sighted. Someone with a better feel for the dials should be able to do much better.
3. Clock BLD speeds are so very much dependent on the scramble. If you got lucky enough to get a scramble where all dials were between 10:00 and 2:00, I would think sub-40 might be possible if you got really fast at memorizing. But if there are a lot of 6:00's, I would think it might be pretty hard for even the very best people to get sub-1 BLD on it. But maybe I'm underestimating the ability of people to reliably do 6:00 turns on clock blindfolded; maybe it's not as hard as I think it is for someone good.
Ok later I'm going to try some clock bld. I should be in a good position to do ok as I'm not too bad at clock sighted and also bld stuff. My method would currently involve solving one piece at a time - i assume this the way you are doing it?
 
(40.293) B' U' R B2 R2 F L2 D B2 L U2 L' D' L2 F' D B2 R2 U2 F' D F2 D' B R2

R D2 R' U2 R D2 R' U2
y' U' L2 U' R2 U L2 U' R2 U2 y
x' R' D' R U' R' D R U x
R' D2 R U R' D2 R U'

U R U' M2 U R' U2 L' U M2 U' L U
x' U L U' M2 U L' U' x
M U2 M U2
U' M2 U R2 U' M2 U R2
x' F L U L' U' M2 U L U' L' M2 x U'
M2 U2 M' U2 M'
 
Last edited:
These are my 5 attempts:
1. 1:50.21 u=-4,d=3 / u=5,d=1 / u=5,d=-3 / u=-5,d=-5 / u=-5 / u=2 / u=0 / u=-1 / u=-1 / d=4 / ddUU
2. 1:33.13 u=-2,d=1 / u=4,d=2 / u=-1,d=0 / u=-3,d=5 / u=6 / u=6 / u=5 / u=5 / u=3 / d=-1 / dUdU
3. DNF u=5,d=-5 / u=1,d=3 / u=-3,d=-1 / u=5,d=0 / u=-4 / u=-1 / u=2 / u=0 / u=0 / d=0 / ddUU
4. 1:34.08 u=3,d=-2 / u=5,d=1 / u=6,d=6 / u=1,d=-5 / u=0 / u=0 / u=0 / u=-5 / u=1 / d=0 / dUdd
5. 1:15.15 u=1,d=6 / u=-5,d=2 / u=-1,d=-3 / u=6,d=-4 / u=3 / u=4 / u=3 / u=-3 / u=5 / d=5 / Uddd

I have some ideas of how to skip a few turns here and there. Atm I use 2 turns for corners, 4 turns for edges, and 3 turns for centres, totalling 46 for a solve. I think I can get it down to 37 turns quite easily though.

EDIT: This is safe turning btw. And memo was probably always around 20-25 secs
 
That's about how I figured you'd do. Which is awesome - good job! I solve it using Stefan Pochmann's method described on his website, which is exactly the same number of turns as you describe. There are quite a few optimizations possible, usually, especially when going from edge to edge - there's almost always an optimization there.

It looks to me like you really might be able to get sub-1 average - looking forward to seeing it! Oh, and I've never seen anyone post a time as fast as 1:15.15 before. UWR? :D
 
Here's an idea for an optimization on clock BLD, Pochmann style. Edges take the most turns and you do the most of them. Here's a way to do two adjacent edges at once in 6 moves (instead of 8), saving 8 turns overall:
- Suppose you're solving the U and R edges. You memorized a turn of a for the U and b for the R.
- Turn (UUdd) and (dddU) by +a.
- Turn (dUdU) and (Uddd) by +b.
- Turn (dUdd) and (UddU) by -(a+b).

And don't forget that if the center ever lines up with an edge (say the hour is a) you can solve them like this, assuming the edge is on top:
- Turn (Uddd) and (dUdd) by -a.
- Turn (UUdd) by +a.
This saves 4 turns with the normal Pochmann solution and 2 with the above optimization.
 
Last edited:
Here's an idea for an optimization on clock BLD, Pochmann style. Edges take the most turns and you do the most of them. Here's a way to do two adjacent edges at once in 6 moves (instead of 8), saving 8 turns overall:
- Suppose you're solving the U and R edges. You memorized a turn of a for the U and b for the R.
- Turn (UUdd) and (dddU) by +a.
- Turn (dUdU) and (Uddd) by +b.
- Turn (dUdd) and (UddU) by -(a+b).

And don't forget that if the center ever lines up with an edge (say the hour is a) you can solve them like this, assuming the edge is on top:
- Turn (Uddd) and (dUdd) by -a.
- Turn (UUdd) by +a.
This saves 4 turns with the normal Pochmann solution and 2 with the above optimization.
Thanks for those - the way I was thinking of saving moves was to just skip AUFs and do them all at the end by adding them up as I go. It seems as though Stefan's method doesn't use AUFs on edges though. To solve the L edge when it is at a hours I do
1. dUdU +a
2. UUdU -a
3. dUUU -a
4. UUUU +a
So essentially I was thinking of skipping the last move and then adding them together for the 4 edges on each side so that I can do the AUF at the end.
Same idea with corners (which of course I use Stefan's method for). Your way seems really nice though (especially the solved edge one) so I'll have a go at it later :)
 
Finally starting to get decent at multi. I won the MBLD event at Naoned Open with 5/5 in 30:18, new French NR :)
My previous PB was 2/2, just lol...
 
Hi guys

Is this scramble lucky??? because it could be my pb.

U' L D' L2 D R' U' B2 R2 L' U R2 B R' D' F D R2 L' B U' F B R L

L2 F L B2 L' F' L B2 L
y' U2 R U L2 U' R' U L2 U y
y M' U' M D M' U M D' y'
y' U M U L2 U' M' U L2 U2 y
y (R') R U' R U R U R U' R' U' R2 (R) y'
y' L' U M' U2 M U L y
x U2 R' E' R U2 R' E R
 
Hi guys

Is this scramble lucky??? because it could be my pb.

U' L D' L2 D R' U' B2 R2 L' U R2 B R' D' F D R2 L' B U' F B R L

L2 F L B2 L' F' L B2 L
y' U2 R U L2 U' R' U L2 U y
y M' U' M D M' U M D' y'
y' U M U L2 U' M' U L2 U2 y
y (R') R U' R U R U R U' R' U' R2 (R) y'
y' L' U M' U2 M U L y
x U2 R' E' R U2 R' E R

I think the general rule is if 20% or more pieces are solved it's considered to be a lucky scramble. However it may depend on the situation, for instance your buffers may be solved.
 
Back
Top