7x7 digital cube problem

Let's see...Call the green side the right side and the orange side the front side. R would be a turn of the right face clockwise, while R_2 would be the second layer (ie the one right behind R), R_3 would be the third, etc. Same goes for F, F_2, F_3...

B_2 (L_3)' (B_2)' R B_2 L_3 (B_2)'

Or, in commutator notation, [B_2 (L_3)' (B_2)', R]

Do it slowly so you see what's going on. If it doesn't work...well, let's hope it does.

Edited to fix mistake--thanks Stefan!
 
Thank You So Much!!!!

I an useing that same program and the seven by seven cube is what i am working on. that algorithm really helped but can you use it for different layers like if the swapped peices were in the center what would you do???
 
Parity!!! Help Please

Ok im working on my seven by seven edges and i have a question on the parity. i have all the edges done but one. I don't have a picture yet but i'll try to post one.

This is the case :

Is you look at one edge the whole thing is in the right order but the center block is in parity compaired to the rest of the final row???

Please is you know the algorithm please post it and which side i should hold it
(with the unsolved edge upper-front or lower-front!!!)
 
Yea everyone always has problems with the centers on bigger cube. Seems like most people can solve the whole thing after they learn to solve the centers. Once you learn to solve a 6 by 6 cube you can really solve any sized cube. They are all the same thing just more pieces.
 
Ok im working on my seven by seven edges and i have a question on the parity. i have all the edges done but one. I don't have a picture yet but i'll try to post one.

This is the case :

Is you look at one edge the whole thing is in the right order but the center block is in parity compaired to the rest of the final row???

Please is you know the algorithm please post it and which side i should hold it
(with the unsolved edge upper-front or lower-front!!!)

It's just the normal pure parity fix for 5x5 on different slices.
 
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