New 3*3 best standard deviation WR :p

[Thomas09]

Ooooohhh, who has teh exact opposite of this? Who is the most inconsistant?

 

[Sa967St]

Ooooohhh, who has teh exact opposite of this? Who is the most inconsistant?

Derrick Eide

he once had an SD of over 9000 for the Sunday Contest.

 

[Thomas09]

Ooooohhh, who has teh exact opposite of this? Who is the most inconsistant?

Derrick Eide

he once had an SD of over 9000 for the Sunday Contest.

I didn't know you over 9000'd, Sarah!

 

[Tyson]

I guess my brother was messing around here:

http://www.worldcubeassociation.org/results/p.php?i=2004MAOT01

At WC 2009.

Oh, Chang Frank? I want to go and edit his name in the WCA database now.

 

[Novriil]

Lol I just found out that my pyraminx times on Est Open were very consistent..
12.63, 12.81, 12.80, DNF(0.00), 12.97 = current avg5: 12.86 (σ = 0.08)

(DNF was the best scramble but I messed the LL up and after I ended the solve time was 18sec and I still had a alg to do)

Too bad that there is only 3x3 SD in the statistics.

(And on magic I've gotten 1.34 average (PB) with SD=0)

 

[Stefan]

I just noticed Cameron Almasi is now #1:
http://www.worldcubeassociation.org/results/statistics.php#11

14.53 14.80 14.55 14.72 14.52
standard deviation 0.11

And I guess it was achieved innocently, given that that's his official record average.

 

[rowehessler]

my 10.39 was .63 SD, when all of my others are over 2 seconds lmfao

 

[Swordsman Kirby]

my 10.39 was .63 SD, when all of my others are over 2 seconds lmfao

US Nationals 08?

 

[Ryanrex116]

I just noticed Cameron Almasi is now #1:
http://www.worldcubeassociation.org/results/statistics.php#11

14.53 14.80 14.55 14.72 14.52
standard deviation 0.11

And I guess it was achieved innocently, given that that's his official record average.

Here is the video if anyone wants to see.

 

[Bryan]

And I guess it was achieved innocently, given that that's his official record average.

I call shenanigans on Vincent's DNF record though...

 

[Ranzha]

And I guess it was achieved innocently, given that that's his official record average.

I call shenanigans on Vincent's DNF record though...

Seconded.

 

[anders]

I just noticed Cameron Almasi is now #1:
http://www.worldcubeassociation.org/results/statistics.php#11

14.53 14.80 14.55 14.72 14.52
standard deviation 0.11

And I guess it was achieved innocently, given that that's his official record average.

Well, I just noticed that Zhen Tang is now #1:
http://www.worldcubeassociation.org/results/statistics.php#11

19.86 19.84 19.78 19.88 19.90
standard deviation 0.04

And I am quite sure that it was not achieved innocently, given that his official record average is five seconds better.

 

[Weston]

I just noticed Cameron Almasi is now #1:
http://www.worldcubeassociation.org/results/statistics.php#11

14.53 14.80 14.55 14.72 14.52
standard deviation 0.11

And I guess it was achieved innocently, given that that's his official record average.

Well, I just noticed that Zhen Tang is now #1:
http://www.worldcubeassociation.org/results/statistics.php#11

19.86 19.84 19.78 19.88 19.90
standard deviation 0.04

And I am quite sure that it was not achieved innocently, given that his official record average is five seconds better.

I doubt that too. Especially since he did it in the first round where his scores wouldn't matter too much. But you never know...

 

[shelley]

Hmmm...

I skimmed through the WCA regulations and nowhere does it state that competitors have to be ranked according to speed (with the exception of multiBLD, where it explicitly states lower times are better when comparing results with the same score). The closest it comes to actually saying this is referring to "best" results.

6a) Awards, prizes or honours may be given to competitors according to the announcement of the competition.

So.. as long as it is clearly announced, a competition could be held in which the winner is not the competitor with the fastest solves, but the one with the best standard deviation in his average. Who wants to host the Standard Deviation Open?

 

[anders]

Well, we have

9f6) In 'Best of x' rounds competitors get x (<= 3) attempts, with the best attempt counting.

9f8) In 'Average of 5' rounds competitors get 5 attempts. Of these 5 attempts, the best and worst attempt are removed, with the mean of the remaining 3 attempts counting.

9f10) In 'Mean of 3' rounds competitors get 3 attempts, with the mean of the 3 attempts counting.

9f13) In 'Mean of' and 'Average of' rounds the order in the results is based on the best average/mean per competitor, with lower meaning better.

where I find it hard to include the standard deviation as a measure of "best" result. Unless you find a creative definition of "attempt". But nothing stops you for hosting an unofficial event (http://www.speedcubing.com/results/)

 

[qqwref]

Best of 1, with an attempt being a standard SD of 5

Perhaps you could break ties by having a faster average win if the SDs are the same.