The Orcuber's Hunt For The Best 3x3 Method

[Martyt7777]

yes, but it is also on the green side

But any piece that is on the yellow side intersects with the other sides. Do all the pieces have to be on the same non-yellow side?

 

[CrossPetrus]

EO was done in the second step already

Wait okay can you go over what the full method is, I’m getting lost in the updates.

 

[acrystal]

But any piece that is on the yellow side intersects with the other sides. Do all the pieces have to be on the same non-yellow side?

There is only 2 sides we care abt, the yellow side and the non-yellow side. So all pieces have to be in the non-yellow side.

 

[acrystal]

Wait okay can you go over what the full method is, I’m getting lost in the updates.

X-Cross -1edge: (LEAVE THIS) (solve right, back, and left white edges)(solve back left pair)
Solve 2nd pair with EO: (DO THIS) (with back right pair)
Solve Last White Edge & 3rd Pair: (DO THIS IF YOU CHOSE THIS OPTION)(with front white edge and front right pair)
WV: (LEAVE THIS)
PLL: (LEAVE THIS)

 

[Michael Wimberly]

… I’m getting 5,951 algs for second pair and eo. I think we might need to change something. Maybe we make the pair and insert it while doing eo?

Just curious, how many algs are there for doing last pair with EO? I just want to know if there should be an algset for this or if I should leave this step as it is, doing EO and just pairing up the last pair without solving it.

 

[Michael Wimberly]

we have to double check on the wiki if the method were making already exists (trust me, it hurts when you spend so much time developing a method only to find out it already exists)

Unfortunately I have experienced that before

 

[CrossPetrus]

Just curious, how many algs are there for doing last pair with EO? I just want to know if there should be an algset for this or if I should leave this step as it is, doing EO and just pairing up the last pair without solving it.

Do you mean like zbls? That’s 302 algs.

 

[CrossPetrus]

X-Cross -1edge: (LEAVE THIS) (solve right, back, and left white edges)(solve back left pair)
Solve 2nd pair with EO: (DO THIS) (with back right pair)
Solve Last White Edge & 3rd Pair: (DO THIS IF YOU CHOSE THIS OPTION)(with front white edge and front right pair)
WV: (LEAVE THIS)
PLL: (LEAVE THIS)

Wait where does sbt come into play? Also do you still want 2nd pair + eo as make the pair intuitively and then insert it while doing eo, or something else? Also this seems like a weird block-in-the-back petrus that’s algorithmitized weirdly.

 

[acrystal]

Wait where does sbt come into play?

SBT comes to play in the third step

Also do you still want 2nd pair + eo as make the pair intuitively and then insert it while doing eo, or something else?

yeah

Also this seems like a weird block-in-the-back petrus that’s algorithmitized weirdly.

its ok

 

[Michael Wimberly]

Do you mean like zbls? That’s 302 algs.

Yes, that's what I meant. I guess that's too many algs. (I've never heard of zbls I had to look it up)

 

[acrystal]

Yes, that's what I meant. I guess that's too many algs. (I've never heard of zbls I had to look it up)

how would ZBLS even show up

 

[Michael Wimberly]

how would ZBLS even show up

Because in my method you solve all of f2l without the last pair

 

[acrystal]

Because in my method you solve all of f2l without the last pair

could you remind me of your method again?

 

[Michael Wimberly]

could you remind me of your method again?

Step 1: Block-building

So for this step you're gonna do all of F2L without the last pair using block building for a lower move count.
Here's an easy way to think about it:
1. Make a 1x2x2 block oriented to the correct centers.
2. Expand that into a 2x2x2 block by adding an edge piece.
3. Expand the 2x2x2 block into a 2x2x3 block.
4. Add 1 more f2l pair and then add the last cross piece to finish this step.

Step 2: EO-Pair

In this step, you do EO and pair up the last f2l pair. This can be done intuitively. The F2L pair doesn't need to be solved into its slot.

Step 3: Winter Variation

This step is quite simple, you just do winter variation for the last pair and OLL.

Step 4: PLL

This step is also quite self-explanatory, just do PLL to finish off the solve.

 

[acrystal]

Step 1: Block-building

So for this step you're gonna do all of F2L without the last pair using block building for a lower move count.
Here's an easy way to think about it:
1. Make a 1x2x2 block oriented to the correct centers.
2. Expand that into a 2x2x2 block by adding an edge piece.
3. Expand the 2x2x2 block into a 2x2x3 block.
4. Add 1 more f2l pair and then add the last cross piece to finish this step.

Step 2: EO-Pair

In this step, you do EO while simultaneously pairing up the last f2l pair. This can be done intuitively though it's quite difficult so I might make an algset in the future if this method gains enough traction. The F2L pair doesn't need to be solved into its slot.

Step 3: Winter Variation

This step is quite simple, you just do winter variation for the last pair and OLL.

Step 4: PLL

This step is also quite self-explanatory, just do PLL to finish off the solve.

but id think that zbls+zbll is worse than wv+pll

 

[Michael Wimberly]

but id think that zbls+zbll is worse than wv+pll

Yeah that's why I'm not doing zbls+zbll

 

[0rcoraCuber21]

the orcubers

I like that would everyone be fine with that?

 

[acrystal]

I like that would everyone be fine with that?

K #ORCUBERS

 

[Michael Wimberly]

Orcubers sounds good

 

[Martyt7777]

I have a method idea. I’ll name it HF-O “Hexagonal Francisco (Orcuber variant)”

1. Build a 223 block
2. Solve PAE (pair and edge). PAE is solving the FR pair and the BR edge at the same time. (algorithmic)
3. Rotate so the 223 block is at the back, then for the rest of the first 2 layers and orient the edges at the same time (HFOLS, algorithmic, ~305 algs)
4. ZBLL (algorithmic, ~493 algs)