U' L' D U2 R2 B2 D' R2 U' L2 F2 D L2 R D F' U2 F2 U2 F'
z y2
R' D' R // cross
L U' L2 U2 L // 1st and 2nd pair
U2 R' U R // 3rd pair
U2 R U2 R' // 4th pair
U2 R U R' U' R' F R2 U R' U' F' // OLL
U // PLL skip
U' L' D U2 R2 B2 D' R2 U' L2 F2 D L2 R D F' U2 F2 U2 F'
z y2 //Inspection
R' D' R //Cross
L U' L2' U2 L //F2L #1 & 2
R U2 R' //F2L #3
U2 R' U' R // F2L #4
. . R U R' U' R' F R2 U R' U' F' //OLL
U //AUF(PLL Skip)
// 27/2.392 = 11.2876254181 TPS
It's actually a very straightforward solve. Cross is pretty easy and then it's four free pairs (the first one cancels into the second one, it might make more sense to think of it as L U' L' for F2L-1 and then L' U2 L for F2L-2). If you're having trouble understanding it, scramble with white on the right and go through the solution again.