Optimal 2 stages last layer solution

Robert-Y

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Given that you have to solve the last layer in 2 steps, what would be the best solution in terms of the number of moves required on average for each turning metric system?

I thinking that perhaps (orientation of edges + permutation of corners) and then (orientation of corners + permutation of edges) aka step 6 + 7 of the Petrus method might be a good idea, (although this is just a weird feeling lol, I don't have any logical explanation behind my thought :P)
 
Ok sorry I meant in 2 stages, you are given the option to do one of the following:

A. 1. COLL + CPLL 2. EOLL + EPLL
B. 1. COLL + EOLL 2. CPLL + EPLL
C. 1. COLL + EPLL 2. CPLL + EOLL
D. 1. CPLL + EOLL 2. COLL + EPLL
E. 1. CPLL + EPLL 2. COLL + EOLL
F. 1. EOLL + EPLL 2. COLL + CPLL

G. 1. COLL 2. CPLL + EOLL + EPLL
H. 1. CPLL 2. COLL + EOLL + EPLL
I. 1. EOLL 2. COLL + CPLL + EPLL
J. 1. EPLL 2. COLL + CPLL + EOLL

K. 1. COLL + CPLL + EOLL 2. EPLL
L. 1. COLL + CPLL + EPLL 2. EOLL
M. 1. COLL + EOLL + EPLL 2. CPLL
N. 1. CPLL + EOLL + EPLL 2. COLL

Which method takes the least number of moves on average?
 
nice thread^^
I like last layer algs xD

OLL/PLL is for fewest moves just bad...10 moves OLL and at least 12 moves PLL sometimes 14 or more.
COLL has a better average, but i think this way just will make sense if you use Petrus method.
In my opinion you're right, the step 6+7 index of Lars Petrus method is the best way to solve the last layer!
If you are not use Petrus, maybe the VH-system makes a good job to orientate the egdes.
Can make for us a complete list of the S6+7 algs including mirrors an inverses? And of course optimal! :)
 
Can make for us a complete list of the S6+7 algs including mirrors an inverses? And of course optimal! :)

Already been done. See here.

I note that I believe mirror cases are not listed separately.
Actually Helmstetter has computed (for face-turn metric) average move counts for many of these possible LL steps. See here. Generally, Helmstetter does not lists mirrors and inverses as separate cases.

I note that "COLL" generally has a different meaning in cubing than the way Robert used it. Robert, I highly recommend not using COLL to mean "corner orientation of the last layer." I think Tiw was using COLL with the normal meaning.
 
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