The Race to Sub-2

[Sa967St]

So, is anyone interested in participating in this race?

hmm, sure I'll join. I average between 2:00-2:30 right now. I need to practice BLD for the Motor City Open anyway

 

[byu]

OK, so should it be average of 5 or average of 12? I want to know what you think

 

[happa95]

Or another option would be who can get the average of 5 with no times over 2 minutes (allowing one DNF or one time over 2 minutes because it's not counted in the average).

I like this idea.

 

[byu]

OK, we'll go with that.

 

[Gparker]

oh i knew that lol, i guess im in but i know i wont win but its good practice

 

[byu]

Don't be so negative. It just may be so that everyone here forgets about BLD in the next few days (not saying its likely) and you end up winning. You never know what will happen.

 

[Gparker]

i guess i dont know whatll happen

I just got my first sub 10 average of 3 so im getting there

 

[Ellis]

I'm in. I've yet to get any sub-2 single, but I rarely practice and could use some extra motivation.

-The winner will be the first person to get an average of 5 solves without any time over 2:00 and a maximum of 1 DNF

This should be changed to "...5 solves with maximum of one DNF or one single time over 2 minutes."

The way it is makes it sound like an average of (1:59, 1:59, 1:59, 1:59, DNF) would be ok when an average of (1:59, 1:59, 1:59, 1:59, 2:01) is not.

 

[byu]

Thanks Ellis, I changed the rules to that.

 

[Sa967St]

-The winner will be the first person to get an average of 5 solves without any time over 2:00 and a maximum of 1 DNF

This should be changed to "...5 solves with maximum of one DNF or one single time over 2 minutes."

The way it is makes it sound like an average of (1:59, 1:59, 1:59, 1:59, DNF) would be ok when an average of (1:59, 1:59, 1:59, 1:59, 2:01) is not.

Wait...what?
Is the average calculated like a normal 3x3x3 speed average, (with the best and worst removed and the remaining 3 averaged) or is it just trying doing 5 consecutive solves with only 0 or 1 of them being a DNF or over 2 mins?

 

[byu]

Sorry for the confusion. The winner will be the first person to get 5 solves where none of them are over 2 minutes and a maximum of 1 DNF is allowed. This is not like a normal speed average.

 

[not_kevin]

I'll join. I need BLD practice anyway... (I avg somewhere in the 2:xx)

 

[MistArts]

Sorry for the confusion. The winner will be the first person to get 5 solves where none of them are over 2 minutes and a maximum of 1 DNF is allowed. This is not like a normal speed average.

You're telling us to purposely DNF a solve over 2 minutes?

 

[Ellis]

Sorry for the confusion. The winner will be the first person to get 5 solves where none of them are over 2 minutes and a maximum of 1 DNF is allowed. This is not like a normal speed average.

You're telling us to purposely DNF a solve over 2 minutes?

I told him to update that, and he did... I don't know why his explanation of it is still the same though.

RULES:

-The winner will be the first person to get an average of 5 solves with maximum of one DNF or one single time over 2 minutes

All times included in the average have to be under 2 minutes... but if you take off the slowest time, that is not actually included in the average. So the worst result can be anything as long there are four times under 2 minutes.

 

[Mike Hughey]

It might be interesting to watch our progress.

My first try (very very bad):
DNF, 2:46.59, 2:12.20, 2:30.53, DNF = DNF

It seems like I always do very badly for a couple of days after a multi attempt (I just did 8/10 two days ago). It seems like doing multi causes me to slow down too much, and I have to work to get back up to speed again. Hopefully this will improve later today or tomorrow.

I might just update this post for a while with additional attempts, rather than continually adding posts to the thread.

This is fun!

 

[Sa967St]

All times included in the average have to be under 2 minutes... but if you take off the slowest time, that is not actually included in the average. So the worst result can be anything as long there are four times under 2 minutes.

it's not really an "average" then.

 

[Mike Hughey]

All times included in the average have to be under 2 minutes... but if you take off the slowest time, that is not actually included in the average. So the worst result can be anything as long there are four times under 2 minutes.

it's not really an "average" then.

Well, it's still an average, but there's nothing saying what the average needs to be. It's just necessary for all but one of the solves to be successful and sub-2.

I think it's a reasonable goal. It's all arbitrary anyway, and I think that if I could get a set of five solves like this, I could really feel like I'm starting to average sub-2. So I'm happy with this goal.

By the way, I did come close to meeting this goal once - a couple of months ago I got the following:
1:54.25 1:54.86 2:54.78 (1:50.65) (3:00.51) = 2:14.63

It was the first 5 solves of my best ever true average 10/12, which was a 2:21.65 average.

 

[Micael]

If I understand, the rule is finally fixed as
"5 consecutives sub-2 with no DNF allowed".

That is ok for me.

Edit: ok I have just read the post of Ellis, 1 DNF or plus-2 is allowed

 

[Ville Seppänen]

eh, isn't it easier to say that atleast 4 of the times must be sub2? Just so everyone understands.

 

[Gparker]

i like what ville said, it should really just be an average and over 2 mins could be the same as a dnf, or otherwise 4 times sub 2.