campos20
Regular
Hi
I'm learning commutators just now (switching from OP to corners). I already know how it works: setup, change, undo, undo or A, B, A', B'. I was having problems figuring out which sticker should go first and where. I came up with a system that helps in that. I discussed it with some (specialist) people here and it looks like a new system, although I'm not sure. Just wanna share, anyway.
I was trying to figure out how to change stickers, having in mind just the letters for the commutator.
In commutators, there's a sticker that goes both in the setup and the change layer. We can call it Base Sticker.
Using speffz, suppose we want to do the commutator ABU, in which A is the buffer (A-BU). We can use L2 as change and D R2 D' as setup. In that case, U would be the base sticker, since it belongs to both setup and change. The buffer and base sticker are different. When that happens, we must follow the order of the commutator A-BU, which means that we have to do the letter B go to the buffer first. To do so, we do D R2 D (which puts the B in DFR) and then do L2 (which puts the letter B in the buffer spot first), then undo undo.
Now, let's consider the commutator A-VU. Change can be L2 and setup U R2 U'. Base sticker is A and now base sticker and buffer are equal. When that happens, we must follow the inverse order or the commutator (A, UV), which means that U must reach the buffer first, which can be accomplished by doing L2. Then U R2 U', undo undo.
Conclusion:
When the base sticker and buffer are different, same order.
When the base sticker and buffer are equal, inverse order.
More examples
# 1
Commutator: C-PL
Buffer: C
Change: D
Setup: R U R'
Base sticker: P
Situation: buffer and base are different, same order.
Execution: R U R' (change buffer and P) then D.
# 2
Commutator: A-HB
Buffer: A
Change: U'
Setup: L' D' L
Base sticker: A
Situation: buffer and base are equal, inverse order (BH).
Execution: U' (change buffer and B) then L' D' L.
Of course, there's no need to discuss conjugates, since it turns general commutators into pure commutators, then everything above applies.
I'm learning commutators just now (switching from OP to corners). I already know how it works: setup, change, undo, undo or A, B, A', B'. I was having problems figuring out which sticker should go first and where. I came up with a system that helps in that. I discussed it with some (specialist) people here and it looks like a new system, although I'm not sure. Just wanna share, anyway.
I was trying to figure out how to change stickers, having in mind just the letters for the commutator.
In commutators, there's a sticker that goes both in the setup and the change layer. We can call it Base Sticker.
Using speffz, suppose we want to do the commutator ABU, in which A is the buffer (A-BU). We can use L2 as change and D R2 D' as setup. In that case, U would be the base sticker, since it belongs to both setup and change. The buffer and base sticker are different. When that happens, we must follow the order of the commutator A-BU, which means that we have to do the letter B go to the buffer first. To do so, we do D R2 D (which puts the B in DFR) and then do L2 (which puts the letter B in the buffer spot first), then undo undo.
Now, let's consider the commutator A-VU. Change can be L2 and setup U R2 U'. Base sticker is A and now base sticker and buffer are equal. When that happens, we must follow the inverse order or the commutator (A, UV), which means that U must reach the buffer first, which can be accomplished by doing L2. Then U R2 U', undo undo.
Conclusion:
When the base sticker and buffer are different, same order.
When the base sticker and buffer are equal, inverse order.
More examples
# 1
Commutator: C-PL
Buffer: C
Change: D
Setup: R U R'
Base sticker: P
Situation: buffer and base are different, same order.
Execution: R U R' (change buffer and P) then D.
# 2
Commutator: A-HB
Buffer: A
Change: U'
Setup: L' D' L
Base sticker: A
Situation: buffer and base are equal, inverse order (BH).
Execution: U' (change buffer and B) then L' D' L.
Of course, there's no need to discuss conjugates, since it turns general commutators into pure commutators, then everything above applies.