Last Layer

julesv

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Hi, I'm starting a new thread going away from my previous 'hey, I'm really really new' one. I was looking at the beginners method, and the last layer part seems really high in algorithms. I heard of a keyhole method or something like that which would lower the number of algorithms needed. Could anybody clarify?
 
Well, if you have one F2L slot plus the LL remaining to be solved, you can use a keyhole method to solve the LL edges. Basically with an LL edge in the slot, you insert it into the LL correctly oriented while bringing a mis-oriented edge in the LL into the slot. It is a little tricky because you want to get to a point where you have three oriented edges in the LL with the fourth edge in the slot, and with two of the LL edges correctly placed with respect to each other, while the third LL edge in the LL is incorrectly placed with respect to the other two. Then you can put the edge that's in the slot where the incorrect LL edge is while bringing the slot edge down into its slot.

But after solving the edges, you'll need to use commutators or other algs to solve the last five corners.
 
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Go for 2-Look OLL and 2-Look PLL at first. practice with them to be fast in them

then (to be faster) memorize all the 21 cases for 1-Look PLL (permuting all cubies in one algorithm)

after u practice alot, try to memorize all the 57 cases for 1-Look OLL one by one (use badmephisto's algorithms they r very easy ones and can be found in his website as well)

good luck with LL :)
 
Well, if you have one F2L slot plus the LL remaining to be solved, you can use a keyhole method to solve the LL edges. Basically with an LL edge in the slot, you insert it into the LL correctly oriented while bringing a mis-oriented edge in the LL into the slot. It is a little tricky because you want to get to a point where you have three oriented edges in the LL with the fourth edge in the slot, and with two of the LL edges correctly placed with respect to each other, while the third LL edge in the LL is incorrectly placed with respect to the other two. Then you can put the edge that's in the slot where the incorrect LL edge is while bringing the slot edge down into its slot.

But after solving the edges, you'll need to use commutators or other algs to solve the last five corners.

Isn't that like MLGS?
 
Well, if you have one F2L slot plus the LL remaining to be solved, you can use a keyhole method to solve the LL edges. Basically with an LL edge in the slot, you insert it into the LL correctly oriented while bringing a mis-oriented edge in the LL into the slot. It is a little tricky because you want to get to a point where you have three oriented edges in the LL with the fourth edge in the slot, and with two of the LL edges correctly placed with respect to each other, while the third LL edge in the LL is incorrectly placed with respect to the other two. Then you can put the edge that's in the slot where the incorrect LL edge is while bringing the slot edge down into its slot.

But after solving the edges, you'll need to use commutators or other algs to solve the last five corners.

Isn't that like MLGS?

No. Nothing like it. More Heise-ish.
 
keyhole is meant to make the middle layer easier/shorter/faster and should be considered as a step between layer-by-layer (beginners) and Fridrich

For the last layer: http://www.speedsolving.com/forum/showthread.php?t=803

Of course, Arnaud is referring to F2L keyhole, not LL edges keyhole.

I know I've seen a YouTube video of someone using LL edges keyhole. I'm not sure if that's what he called the technique. I don't remember which video it was.
 
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