Which alg do you prefer to solve (fill in the blank)

[unsolved]

This isn't a "Request An Alg" thread, it's more like an "I use this alg, what do you use?" thread.

I'm just wondering what people use to solve this:

R U' F' B L U' F L' U B' F R' U F'

Is there a solution with fewer moves? How about one with the same number of moves that is better for speed solving?

Ditto for this one:

2R2 F2 U2 2R U2 2R2 F2 2R U2 2R2 U2 F2 2R F2

 

[YouCubing]

for the first one I use M' U M' U M' U2 M U M U M U2, and I think a lot of other people also use that
for the second one, that's really cool if you do a 2L' at the beginning and then 2 T-perms and then 2L at the end then you get a better OLL parity than the one I use xD

 

[Aaron Lau]

are you referring to the 1lll or the oll?

 

[Lid]

For speed:
1st: (M' U')*4 (U' M')*4
2nd: Ll' U2 Ll' U2 F2 Ll' F2 Rr U2 Rr' U2 Ll2

 

[unsolved]

for the first one I use M' U M' U M' U2 M U M U M U2, and I think a lot of other people also use that

Yeah for the 3x3x3 I definitely use it. But my 5x5x5 solver counts that as 24 moves since each slice = 1 move. I thought the alg it spit out was weird.

https://alg.cubing.net/?type=alg&puzzle=5x5x5&alg=m-_U_m-_U_m-_U2_m_U_m_U_m_U2&title=Which alg do you use to solve this?&view=playback

for the second one, that's really cool if you do a 2L' at the beginning and then 2 T-perms and then 2L at the end then you get a better OLL parity than the one I use xD

Glad you like it.

For speed:
1st: (M' U')*4 (U' M')*4

Yeah that has to be the fastest I would say!

2nd: Ll' U2 Ll' U2 F2 Ll' F2 Rr U2 Rr' U2 Ll2

Did you mean like this?

https://alg.cubing.net/?type=alg&pu...h alg do you use to solve this?&view=playback

 

[SenorJuan]

The first one I would do Old Skool as
y x' M' (F M')2 F M2 (F M')3 F2
or the same alg without the x' , with U,M moves.

 

[unsolved]

The next one on my list that I'm not sure if there is a faster/better way:

2B U2 2B U2 R' F R' 2B R F' R 2F' U2 2F U2 2B2

Is this the most difficult (i.e. greatest number of moves) for a last layer 2-cycle for the 5x5x5?