Dene
Premium Member
I was wondering if anyone has worked on thisfor 4x4x4 and 5x5x5:
First: Get 2 opposite centers solved.
Second: Get 8 edges solved and place around the two opposite centers.
Third: Solve remaining 4 centers while keeping the 8 solved edges safe.
Fourth: Solve remaining 4 edges.
This is opposed to, getting all centers, then all edges.
I assume this is done, at least by someone? I have been doing this for a while now, and much prefer it to centers first. It makes a lot of sense as 8 edges can be solved very quickly, and then every time you turn a center a half turn, it's just 2 quick finger tricks to get the edges safe again, instead of having to constantly mutilate your solved centers.
Also, particularly for 4x4x4, there is a high chance that after finishing the centers, there will be at least one, sometimes two, of the remaining 4 edges already solved.
Sorry I've been using "solved" instead of "paired" as for a 5x5x5 there are 3 cubies to an edge, not exactly a pair
.
First: Get 2 opposite centers solved.
Second: Get 8 edges solved and place around the two opposite centers.
Third: Solve remaining 4 centers while keeping the 8 solved edges safe.
Fourth: Solve remaining 4 edges.
This is opposed to, getting all centers, then all edges.
I assume this is done, at least by someone? I have been doing this for a while now, and much prefer it to centers first. It makes a lot of sense as 8 edges can be solved very quickly, and then every time you turn a center a half turn, it's just 2 quick finger tricks to get the edges safe again, instead of having to constantly mutilate your solved centers.
Also, particularly for 4x4x4, there is a high chance that after finishing the centers, there will be at least one, sometimes two, of the remaining 4 edges already solved.
Sorry I've been using "solved" instead of "paired" as for a 5x5x5 there are 3 cubies to an edge, not exactly a pair