Trying to Locate L5C algorithms for 3x3

[pTr]

for the U face and FR corners.

Thanks
- pTr

 

[Fred]

This is what I thought of first: https://www.speedsolving.com/thread...smissed-3x3-method-now-fully-developed.87166/

But if you want L5C as the last step of your solve, you'd need other algs.

 

[pTr]

could I just use 5s? I mean it's not all of 5s but like just some of it from one spot?

 

[That0newe1rdo]

could I just use 5s? I mean it's not all of 5s but like just some of it from one spot?

5s ? 5 style ?

 

[pTr]

before you start yapping about how 5s is dumb and kinda not worth it as a whole alg set, I would just be using some of it... idk how many that is. but it would be the only algorithm set in my method.

 

[Martyt7777]

5! = 120 (corner permutations)
3^5 = 243 (corner orientations)
due to parity we have to divide by 12

120 * 243 / 12 = 2,430

I could be wrong but I think 2430 is the amount of algs

 

[pTr]

ummm... idk...

I would do that math more intuitively like c and go to 12 spots after that c - b can go to 9 spots then 6 then 3 so like 1944...

yeah... that might not be worth it...

 

[That0newe1rdo]

ummm... idk...

I would do that math more intuitively like c and go to 12 spots after that c - b can go to 9 spots then 6 then 3 so like 1944...

yeah... that might not be worth it...

CPLC is only like 26/28 algs

 

[pTr]

what's that?

 

[Fred]

5! = 120 (corner permutations)
3^5 = 243 (corner orientations)
due to parity we have to divide by 12

120 * 243 / 12 = 2,430

I could be wrong but I think 2430 is the amount of algs

You only divide by 6: 3 for corner orientation and 2 for corner permutation, so there are 4860 cases.

 

[That0newe1rdo]

what's that?

Just an algset that permutes the last 5 corners, and the DFR corner is completely solved.