Square-1 Corner Parity?

[aliengrey]

Well I'm finally learning to solve my Square-1, but I seem to keep getting a corner parity? I thought there was only edge parity? I just need to swap two corners that are next to each other.

 

[masterofthebass]

if you only have 2 corners to swap. Then you can swap 2 edges and get rid of parity. Unless you are doing a method with different steps than Lars', you shouldn't be getting that.

 

[aliengrey]

if you only have 2 corners to swap. Then you can swap 2 edges and get rid of parity. Unless you are doing a method with different steps than Lars', you shouldn't be getting that.

I don't know what method it is. I tried to learn Lars but had trouble understanding it, so I used Thrawst's YouTube tutorial.

 

[blade740]

There should be an algorithm to do a J perm, which turns corner parity into edge parity.

 

[aliengrey]

There should be an algorithm to do a J perm, which turns corner parity into edge parity.

Yeah, Thrawst answered my question on his YouTube tutorial. You just use the Permutation Alg.

 

[AvGalen]

I know your question has already been answered, but I would just like to tell you that corners can be entirely done by 1 simple alg:
/ (3,0) / (-3,-3) / (0,3) /

If you only need to swap 2 adjacent corners, just do Alg (3,0) Alg. If you need to swap 2 opposite corners, just do Alg (6,0) Alg. If the corners you need to swap are on the bottom: Alg (0,3) Alg and Alg (0,6) Alg.

It's that easy and very intuitive