Speed/Method

[Dcuber]

Hey

so far, i've only been averaging around 43 seconds
What do u guys think is the best method 2 speedsolve?(fridrich, Lars, Roux..)
Right now i'm doing the fridrich method, but i only expect myself 2 go nmo more than the 2-look OLL
and i'm prob. not gonna learn the g perms until i find a way to identify them

Plz help
:confused:
Thx

Dcuber

 

[AvGalen]

Fridrich has proven to be the fastest so far
Petrus (by Lars) has only a couple of really fast users.
Roux (by Gilles) has only a couple of really fast users too.

All these 3 methods can get you under 15 seconds on average, but only if you really learn them and practice them a lot!

 

[Johannes91]

If you're averaging over 30 seconds, don't worry "which method is the fastest" (whatever that means).

In my opinion, getting good at several different methods is a necessity if you want to become a good cuber.

 

[Dcuber]

thxs

but which 1 is the easiest to learn?

 

[Erik]

easiest would probably be petrus, but the easiest to get fast with is probably CFOP (Fridrich) since blockbuilding takes more intuition

 

[badmephisto]

easiest would be petrus. There are less cases in it. But intuition should tell you that less cases => higher times, most of the time

And identifying Gperms is actually quite easy. Align the 2x1x1 solved block with its color by doing U/U'/U2 to 'solve' it. Then turn the cube in your hands doing y/y' to have the two corners with matching sticker colors on left. Then the location of that 2x1x1 block will clearly tell you which Gperm to use. I think there is a video on this on youtube, try to search for it.

 

[Dene]

Or alternatively, every time you get to a G-permutation (which I understand is one (four) of the most common), just stop, take your time, and analyse which one you need to use, find a familiar pattern that works for you.

 

[Skrato]

Or alternatively, every time you get to a G-permutation (which I understand is one (four) of the most common), just stop, take your time, and analyse which one you need to use, find a familiar pattern that works for you.

I found a reasonable fast way, and might as well use it here. There are 4 g-perms, and straight away you look at the corners to see if they need to be cycled clockwise or anti. That way you eliminate 2 of them in one step. Then you can tell which one to use by the position of the 2x1x1 block =)

 

[Johannes91]

easiest would be petrus. There are less cases in it.

With that logic, Heise is easier. You don't need to memorize anything.

Learning to find solutions on your own is much harder than blindly memorizing some.

But intuition should tell you that less cases => higher times, most of the time

I can't figure out what's the reasoning behind that.

 

[Swordsman Kirby]

easiest would be petrus. There are less cases in it. But intuition should tell you that less cases => higher times, most of the time

Less cases? That's wrong: If that were true, then there would probably be more Petrus users.

Less cases implies higher times? That's wrong: If that were true, then there wouldn't be too many Fridrich users for F2L.

 

[Dyste]

You mean there woud be even less people learning ZB. xD