SD?

[byu]

In my opinion, the slower you are, the higher your SD should be. For example, if you average 1:50 on the cube, you'd probably get several solves between 1:40 and 2:00 often. If you average 12 seconds, you're most likely only going to get solves between 11.5 - 12.5, therefore getting a lower SD (I think)

 

[tlm1992]

Standard deviation is always Less than or equal to 1 or greater than or equal to -1.

If you are taking the longest time- the shortest time, then that is the range.

I'm to lazy to see if this would work, but if you'd like to calculate actual SD, I'll test it and post my results and how to do it.

What? I don't get that at all...

The absolute value is always less than or equal to 1. It can be any decimal, but it can't be 1.1 because it's greater than 1. It CAN be .5, .67, or -.9

Um... I will give you a counterproof right now. Find the sd of this set of 12:
1,2,3,4,5,6,7,8,9,10,11,9001

Perhaps you're thinking of correlation coefficient?

I'll ask my teacher tomorrow, because she's been teaching it as Standard deviation. But now that I look it up, it's something I've never dealt with before??? Now I'm confused. :confused:

standard deviation is hard to explain without using any numbers, so i'll use some random simple numbers to explain:

say you have these times: 18.00, 21.00, 19,00, 21.00, 23.00
the avg. of these are: 20.4

Then you subtract the avg. from each single solve and square them. Then you get the numbers:

2.56, 0.36, 1.96, 0.36, 6.76

then you avg. these times and you have found your standrad deviation: 2.4

these numbers might not be right, i'm i bit tired, but i hope you get the point

 

[not_kevin]

standard deviation is hard to explain without using any numbers, so i'll use some random simple numbers to explain:

say you have these times: 18.00, 21.00, 19,00, 21.00, 23.00
the avg. of these are: 20.4

Then you subtract the avg. from each single solve and square them. Then you get the numbers:

2.56, 0.36, 1.96, 0.36, 6.76

then you avg. these times and you have found your standrad deviation: 2.4

these numbers might not be right, i'm i bit tired, but i hope you get the point

Good explanation, but I think you only found the variance. The SD is the square root of the variance (about 1.55 in this example).