jimbolicious86
Member
- Joined
- Apr 24, 2011
- Messages
- 4
I'm an idiot. It's just an H Perm that needs a U2...
Original post:
I've found a PLL case that doesn't have a 1 step algorithm (at least not that I could find on the internet). I've "written" an OLL algorithm for myself by modifying one of Fridrich's algs but have never attempted writing an alg from scratch. It's a variation of the E-permutation case. Instead of two sets of adjacent corners being swapped , they have been swapped diagonally. All four edges are oriented and permuted correctly (like the normal E-Permutation case) but all four corners have colors opposite of BOTH of the side faces on which the piece is placed. To set up the case, do an E-Perm, then turn the cube so your last layer is perpendicular to your first E-Perm execution (y or y' if your last layer is on the U face). You can also set it up by performing an N-Perm and then its mirror (this is how I plan to solve it unless I find a devoted algorithm because I don't mind my N-Perms and I think it will be faster for me than doing an E-perm twice). The two times I've gotten this case (it's rare), I have been solving my V cube 5 but the case is possible on all cubes (and I would imagine would probably happen more often on a 2x2x2 due to the lack of edge pieces). Let me know if you guys have any ideas. I use 1 look OLL and 1 look PLL if that helps.
Original post:
I've found a PLL case that doesn't have a 1 step algorithm (at least not that I could find on the internet). I've "written" an OLL algorithm for myself by modifying one of Fridrich's algs but have never attempted writing an alg from scratch. It's a variation of the E-permutation case. Instead of two sets of adjacent corners being swapped , they have been swapped diagonally. All four edges are oriented and permuted correctly (like the normal E-Permutation case) but all four corners have colors opposite of BOTH of the side faces on which the piece is placed. To set up the case, do an E-Perm, then turn the cube so your last layer is perpendicular to your first E-Perm execution (y or y' if your last layer is on the U face). You can also set it up by performing an N-Perm and then its mirror (this is how I plan to solve it unless I find a devoted algorithm because I don't mind my N-Perms and I think it will be faster for me than doing an E-perm twice). The two times I've gotten this case (it's rare), I have been solving my V cube 5 but the case is possible on all cubes (and I would imagine would probably happen more often on a 2x2x2 due to the lack of edge pieces). Let me know if you guys have any ideas. I use 1 look OLL and 1 look PLL if that helps.
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