# of Skewb states

BN

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I've looked around everywhere and can't find anything on the number of possible states of a Skewb. I'm sure one of you guys can help out.
 
I guess one could try to memorize all of the "EG" method on Skewb (I'm not an expert, but it can't be bigger than ZBLL and some people know full ZBLL)
Basically just solve a side and solve the rest (Has anyone thought of this?)

Isn't this just Sarah's Advanced method?
 
I guess one could try to memorize all of the "EG" method on Skewb (I'm not an expert, but it can't be bigger than ZBLL and some people know full ZBLL)
Basically just solve a side and solve the rest (Has anyone thought of this?)

Sarah's advanced is 134 cases, so including diagonal swap that's 268 total, which is considerably less than ZBLL.
 
This idea has been explored to some extend. From what I know the reason why nobody did further work on that is because most algs can be considered ugly and it's simply not worth it.
But there is a different method being worked on right now which is closed to be finished where you build a layer with 1 twisted corner. Then you do a step similar to Sarah's intermediate method which has 90 different cases and you're left with a L4C case.
The algs range from 4-8 moves but most are 7 moves long and mostly consist of getting a corner out and inserting it in some fancy way which is much easier to do than fixing an "EG" face on Skewb.

Oh btw as this thread is about the number of Skewb states.. could somebody calculate how much moves you need max to build a layer with a twisted corner and how many moves you need on average. I think it would be good to know to test the effectiveness of the method explained above :D
 
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